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kvasek [131]
3 years ago
15

Two cannonballs are dropped from a second-floor physics lab at height h above the ground. Ball B has four times the mass of ball

A. When the balls pass the bottom of a first-floor window at height above the ground, the relation between their kinetic energies, KA and KB, is
Physics
1 answer:
denpristay [2]3 years ago
3 0

Answer:

1:4

Explanation:

The formula for calculating kinetic energy is:

KE=\dfrac{1}{2}mv^2

If the mass is multiplied by 4, then, the kinetic energy must be increased by 4 as well. Since they will be travelling at the same speed when they are at the same point, the relation between KA and KB must be 1:4 or 1/4. Hope this helps!

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In the far future, astronauts travel to the planet Saturn and land on Mimas, one of its 62 moons. Mimas is small compared with t
Mamont248 [21]

Answer:

a)h_{max}=14536.16 m

b)h = 15687.9 m

c)PD=7.62\% The estimate is low.

Explanation:

a) Using the energy conservation we have:

E_{initial}=E_{final}

we have kinetic energy intially and gravitational potential energy at the maximum height.

\frac{1}{2}mv^{2}=mgh_{max}

h_{max}=\frac{v^{2}}{2g}

h_{max}=\frac{43^{2}}{2*0.0636}

h_{max}=14536.16 m  

b)  We can use the equation of the gravitational force

F=G\frac{mM}{R^{2}}   (1)

We have that:

F = ma    (2)

at the surface G will be:

G=\frac{gR^{2}}{M}

Now the equation of an object at a distance x from the surface.

is:

F=\frac{mgR^{2}}{(R+x)^{2}}

m\frac{dv}{dt}=\frac{mgR^{2}}{(R+x)^{2}}

Using that dv/dt is vdx/dt and integrating in both sides we have:

v_{0}=\sqrt{\frac{2gRh}{R+h}}

h=\frac{v_{0}^{2}R}{2gR-v_{0}^{2}}

h=15687.9

c) The difference is:

So the percent difference will be:

PD=|\frac{14536.16-15687.9}{(14536.16+15687.9)/2}*100%

PD=7.62\%

The estimate is low.

I hope it helps you!

7 0
3 years ago
a boy standing by a lake sees a fish in the pond and tries to thrust a spear into it he will success or not​
almond37 [142]

Answer:

yes

Explanation:

8 0
3 years ago
Read 2 more answers
A meteorite has a speed of 90.0 m/s when 850 km above the Earth. It is falling vertically (ignore air resistance) and strikes a
Schach [20]

Before it hits the sand bed, the meteorite is accelerating uniformly with g=9.80\dfrac{\rm m}{\mathrm s^2}, so that its speed v satisfies

v^2-{v_0}^2=-2g\Delta y

where v_0=90.0\dfrac{\rm m}{\rm s} is its initial speed and \Delta y=(0-850)\,\mathrm{km}=-850\,\mathrm{km} is its change in altitude. Notice that we're taking the meteorite's starting position in the atmosphere to be the origin, and the downward direction to be negative. Now,

v^2-\left(-90.0\dfrac{\rm m}{\rm s}\right)^2=-2\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)(-850,000\,\mathrm m)\implies\boxed{v=4080\dfrac{\rm m}{\rm s}}

3 0
3 years ago
A car goes from point A to point B, five miles away and then returns to point A. The car is going 15 mph.
Alex73 [517]

Answer: B) 0 mph

Explanation:

Velocity is a vector quantity. It can be measured as rate of change of displacement.

velocity\frac{Displacement}{time}

Displacement is the straight path length between final and initial position of the body in motion.

It is given that the car goes from point A to point B and the returns to Point A. Hence, the net displacement of the car is 0 as the car comes back to its initial position.

Therefore, the velocity of the car is 0 mph.

Option B is correct.

3 0
3 years ago
A 400.0 kg storage box is held 10 m above ground by a forklift. What is its gravitational potential energy? (PE = mgh)
Kobotan [32]

Answer:

The gravitational potential energy (PE) of a particle or a system of particles is a form of energy that exists due to its position. Mathematically, it is expressed as the product of mass, gravitational acceleration, and the vertical displacement.

Explanation:

Given data:

Mass of the storage box, m = 400.0 \ kg

Height, h = 10 \ m

The gravitational potential energy of the storage box can be expressed as,

PE = mgh

PE = 400.0 \times 9.80 \times 10

PE = 39200 \ \rm J.

8 0
3 years ago
Read 2 more answers
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