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Inessa05 [86]
3 years ago
11

The Moon takes about 27 days to orbit the Earth. Assuming a circular orbit, how fast is it orbiting? Express your answer in km/h

r.
Physics
1 answer:
Vinvika [58]3 years ago
7 0

Answer:

3727.24km/h

Explanation:

Hello!

To solve this problem we must first know what is the distance from the earth to the moon, this will be our radius.

=384400Km

Then we find the distance traveled which would be the perimeter of a circle = 2πr, finally to find the speed we divide the distance traveled by 27 days.

Finally we use conversion factor to have the speed in km / h

solving

perimeter= 2(3.14)r=2(3.14)(384400Km)=2415256.432km\\Speed=\frac{2415256.432km}{27days} *\frac{1day}{24h} =3727.24km/h

the moon is orbiting at speed of 3727.24km/h

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babunello [35]

Answer:

The impulse applied by the stick to the hockey park is approximately 7 kilogram-meters per second.  

Explanation:

The Impulse Theorem states that the impulse experimented by the hockey park is equal to the vectorial change in its linear momentum, that is:

I = m\cdot (\vec{v}_{2} - \vec{v_{1}}) (1)

Where:

I - Impulse, in kilogram-meters per second.

m - Mass, in kilograms.

\vec{v_{1}} - Initial velocity of the hockey park, in meters per second.

\vec{v_{2}} - Final velocity of the hockey park, in meters per second.

If we know that m = 0.2\,kg, \vec{v}_{1} = -10\,\hat{i}\,\left[\frac{m}{s}\right] and \vec {v_{2}} = 25\,\hat{i}\,\left[\frac{m}{s} \right], then the impulse applied by the stick to the park is approximately:

I = (0.2\,kg)\cdot \left(35\,\hat{i}\right)\,\left[\frac{m}{s} \right]

I = 7\,\hat{i}\,\left[\frac{kg\cdot m}{s} \right]

The impulse applied by the stick to the hockey park is approximately 7 kilogram-meters per second.  

8 0
3 years ago
Correlation is:
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Answer: The answer is B

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