We will first record its mass and then its volume by measuring its dimensions
then divide mass by volume and will get density of regular solid
Answer:
The velocity of the ball before it hits the ground is 381.2 m/s
Explanation:
Given;
time taken to reach the ground, t = 38.9 s
The height of fall is given by;
h = ¹/₂gt²
h = ¹/₂(9.8)(38.9)²
h = 7414.73 m
The velocity of the ball before it hits the ground is given as;
v² = u² + 2gh
where;
u is the initial velocity of the on the root = 0
v is the final velocity of the ball before it hits the ground
v² = 2gh
v = √2gh
v = √(2 x 9.8 x 7414.73 )
v = 381.2 m/s
Therefore, the velocity of the ball before it hits the ground is 381.2 m/s
It would be both speed and direction depending on the man's swing
Answer:
D = 2.38 m
Explanation:
This exercise is a diffraction problem where we must be able to separate the license plate numbers, so we must use a criterion to know when two light sources are separated, let's use the Rayleigh criterion, according to this criterion two light sources are separated if The maximum diffraction of a point coincides with the first minimum of the second point, so we can use the diffraction equation for a slit
a sin θ = m λ
Where the first minimum occurs for m = 1, as in these experiments the angle is very small, we can approximate the sine to the angle
θ = λ / a
Also when we use a circular aperture instead of slits, we must use polar coordinates, which introduce a numerical constant
θ = 1.22 λ / D
Where D is the circular tightness
Let's apply this equation to our case
D = 1.22 λ / θ
To calculate the angles let's use trigonometry
tan θ = y / x
θ = tan⁻¹ y / x
θ = tan⁻¹ (4.30 10⁻² / 140 10³)
θ = tan⁻¹ (3.07 10⁻⁷)
θ = 3.07 10⁻⁷ rad
Let's calculate
D = 1.22 600 10⁻⁹ / 3.07 10⁻⁷
D = 2.38 m
The displacement of the object as determined from the velocity-time graph is 562.5 m.
<h3>What is a velocity-time graph?</h3>
A velocity-time graph is a graph of the velocity of an object plotted in the vertical or y-axis of the graph against the time taken on the horizontal or x-axis.
The displacement of an object can be obtained from its velocity-time graph by calculating the total area under the graph.
The total area under the graph = area of triangle + area of rectangle
Area of triangle = b*h/2 =
Area of triangle = 25 * (35 - 10)/2 = 312.5 m
Area of rectangle = l * b
Area of rectangle = 10 * 25 = 250 m
Total area = (312.5 + 250) m
Total area = 562.5 m
Therefore, the displacement of the object is 562.5 m
In conclusion, the total area of a velocity-time graph gives the displacement.
Learn more about velocity-time graph at: brainly.com/question/28064297
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