<span>The total amount of kinetic energy and potential energy within a system is called "Mechanical Energy"
In short, Your Answer would be Option C
Hope this helps!</span>
Answer:
24volts
Explanation:
If a 15-µF capacitor is charged to 40V, the charge across the capacitor can be calculated using the formula;
Q = CV where;
Q is the charge flowing across the capacitor
C is the capacitance of the capacitor. = 15-µF
V is the voltage = 40V
Q = 15×10^-6×40
Q = 0.0006coulombs
If the charge of 0.0006coulombs is then connected across an initially uncharged 25-µF capacitor, the potential difference across the 25-µF can be calculated using the initial expression;
Q = CV
V = Q/C
V = 0.0006/25×10^-6
V = 24Volts
Therefore, the final potential difference across the 25-µF capacitor will be 24volts
Answer:
At 3.86K
Explanation:
The following data are obtained from a straight line graph of C/T plotted against T2, where C is the measured heat capacity and T is the temperature:
gradient = 0.0469 mJ mol−1 K−4 vertical intercept = 0.7 mJ mol−1 K−2
Since the graph of C/T against T2 is a straight line, the are related by the straight line equation: C /T =γ+AT². Multiplying by T, we get C =γT +AT³ The electronic contribution is linear in T, so it would be given by the first term: Ce =γT. The lattice (phonon) contribution is proportional to T³, so it would be the second term: Cph =AT³. When they become equal, we can solve these 2 equations for T. This gives: T = √γ A .
We can find γ and A from the graph. Returning to the straight line equation C /T =γ+AT². we can see that γ would be the vertical intercept, and A would be the gradient. These 2 values are given. Substituting, we f ind: T =
√0.7/ 0.0469 = 3.86K.
Answer:
a) 360 kQ
b) 4.32 MJ
c) 1200 W-h
Explanation:
a) The definition of the current is.

having a count that 10 hours = 36.000 s

![Q = 36000*10 = 360.000 [Q]](https://tex.z-dn.net/?f=%20Q%20%3D%2036000%2A10%20%3D%20360.000%20%5BQ%5D%20)
b) The definition of the Energy in power terms is.

and the definition of power is:
![P = V*I = 12 * 10 = 120 [W]](https://tex.z-dn.net/?f=%20P%20%3D%20V%2AI%20%3D%2012%20%2A%2010%20%3D%20120%20%5BW%5D)
replacing in the energy formula.

solving the integral, have into account that t is in seconds.
![E=P*t=120*36000=4.320.000=4.32 [MJ]](https://tex.z-dn.net/?f=%20E%3DP%2At%3D120%2A36000%3D4.320.000%3D4.32%20%5BMJ%5D)
c) The energy in W-h, we can find it multiplying power by hours
.
Yes, an object<span> that was set in motion in the past by some force, but that is no longer being acted on by a net force, is </span>moving<span> but with </span>zero acceleration<span>, i.e. it is </span>moving<span> at constant velocity.</span>