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Anvisha [2.4K]
3 years ago
14

A certain bridge is 4,224 feet long. What constant rate, in miles per hour, must be maintained in order to walk across the bridg

e in 12 minutes? (1 mile = 5,280 feet)
Physics
1 answer:
Archy [21]3 years ago
4 0

Answer:

4miles/hour

Explanation:

the solution for this question requires that the quantities are converted to the appropriate units as required by the question.

Rate in miles per hour = distance in miles / time in hour

to convert 12 minutes to hours; recall that 60 minutes make 1 hour

12 minutes to hour = 12/60 = 0.2hr

to convert 4224 feet to miles; recall 5280 feet is equivalent to 1 mile

4224 feet to miles = 4224/5280 = 0.8 miles

∴ rate = 0.8 / 0.2

rate = 4 miles per hour

the constant rate in miles per hour = 4 miles/hour

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The total amount of kinetic energy and potential energy within a system is called
Alekssandra [29.7K]
<span>The total amount of kinetic energy and potential energy within a system is called "Mechanical Energy"

In short, Your Answer would be Option C

Hope this helps!</span>
6 0
3 years ago
A 15-µF capacitor is charged to 40 V and then connected across an initially uncharged 25-µF capacitor. What is the final potenti
Kobotan [32]

Answer:

24volts

Explanation:

If a 15-µF capacitor is charged to 40V, the charge across the capacitor can be calculated using the formula;

Q = CV where;

Q is the charge flowing across the capacitor

C is the capacitance of the capacitor. = 15-µF

V is the voltage = 40V

Q = 15×10^-6×40

Q = 0.0006coulombs

If the charge of 0.0006coulombs is then connected across an initially uncharged 25-µF capacitor, the potential difference across the 25-µF can be calculated using the initial expression;

Q = CV

V = Q/C

V = 0.0006/25×10^-6

V = 24Volts

Therefore, the final potential difference across the 25-µF capacitor will be 24volts

6 0
3 years ago
Read 2 more answers
At which temperature do the lattice and conduction electron contributions to the specific heat of Copper become equal.
sp2606 [1]

Answer:

At 3.86K

Explanation:

The following data are obtained from a straight line graph of C/T plotted against T2, where C is the measured heat capacity and T is the temperature:

gradient = 0.0469 mJ mol−1 K−4 vertical intercept = 0.7 mJ mol−1 K−2

Since the graph of C/T against T2 is a straight line, the are related by the straight line equation: C /T =γ+AT². Multiplying by T, we get C =γT +AT³ The electronic contribution is linear in T, so it would be given by the first term: Ce =γT. The lattice (phonon) contribution is proportional to T³, so it would be the second term: Cph =AT³. When they become equal, we can solve these 2 equations for T. This gives: T = √γ A .

We can find γ and A from the graph. Returning to the straight line equation C /T =γ+AT². we can see that γ would be the vertical intercept, and A would be the gradient. These 2 values are given. Substituting, we f ind: T =

√0.7/ 0.0469 = 3.86K.

4 0
3 years ago
A typical rechargeable deep-cycle battery for an electric trolling motor (fishing boat) delivers 10A of current at a voltage of
Oksi-84 [34.3K]

Answer:

a) 360 kQ

b) 4.32 MJ

c) 1200 W-h

Explanation:

a) The definition of the current is.

I= \frac{Q}{t}

having a count that 10 hours = 36.000 s

Q = I*t

Q = 36000*10 = 360.000 [Q]

b) The definition of the Energy in power terms is.

E = \int\limits^{t}_{0} {P} \, dt

and the definition of power is:

P = V*I = 12 * 10 = 120 [W]

replacing in the energy formula.

E = \int\limits^{36.000}_{0} {120} \, dt

solving the integral, have into account that t is in seconds.

E=P*t=120*36000=4.320.000=4.32 [MJ]

c) The energy in W-h, we can find it multiplying power by hours

E = P*t =120*10 = 1200 W-h.

3 0
3 years ago
#86 can an object be moving when its acceleration is zero? can an object be accelerating when its speed is zero?
liraira [26]
Yes, an object<span> that was set in motion in the past by some force, but that is no longer being acted on by a net force, is </span>moving<span> but with </span>zero acceleration<span>, i.e. it is </span>moving<span> at constant velocity.</span>
7 0
3 years ago
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