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Alex787 [66]
3 years ago
5

Suppose the average yearly salary of an individual whose final degree is a masters is $49 thousand less than twice that of an in

dividual whose final degree is a bachelors. Combined two people with each of the educational attainments earn $113 thousand
Mathematics
1 answer:
Anika [276]3 years ago
4 0

Answer:

Masters = 59,000

Bachelors = 54,000

Step-by-step explanation:

Given that:

individual whose final degree is a masters is $49 thousand less than twice that of an individual whose final degree is a bachelors

Let masters salary = m

Bachelors salary = b

m = 2b - 49000 - - - (1)

m + b = 113,000 - - - (2)

From (2)

m = 113,000 - b

Substitute m = 113,000 - b into (1)

113,000 - b = 2b - 49000

113000 + 49000 = 2b + b

162000 = 3b

b = 162000/3

b = $54000

Hence,

Masters salary :

m = 113,000 - b

m = 113,000 - 54,000

m = 59,000

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Answer:

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Step-by-step explanation:

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A=\pi r^2

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Substitute:

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Step-by-step explanation:

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3 years ago
The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d
kozerog [31]

Answer: 49.85%

Step-by-step explanation:

Given : The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The distribution of the number of daily requests is bell-shaped ( normal distribution ) and has a mean of 61 and a standard deviation of 9.

i.e.  \mu=61 and \sigma=9

To find :  The approximate percentage of lightbulb replacement requests numbering between 34 and 61.

i.e. The approximate percentage of lightbulb replacement requests numbering between 34 and 34+3(9).

i.e. i.e. The approximate percentage of lightbulb replacement requests numbering between \mu and \mu+3(\sigma). (1)

According to the 68-95-99.7 rule, about 99.7% of the population lies within 3 standard deviations from the mean.

i.e. about 49.85% of the population lies below 3 standard deviations from mean and 49.85% of the population lies above 3 standard deviations from mean.

i.e.,The approximate percentage of lightbulb replacement requests numbering between \mu and \mu+3(\sigma) = 49.85%

⇒ The approximate percentage of lightbulb replacement requests numbering between 34 and 61.= 49.85%

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Answer: I wouldn’t be able to make a linear system right now, but it would be better to use Hamster Fun if it were long-term, and Hamster Heaven if it were short-term.

Step-by-step explanation:

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