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2 years ago

2 geometry questions.. will mark brainliest

Mathematics

1 answer:

Andru [333]2 years ago

3 0

Answer to one im pretty sure is 136.4 degrees and to number 2 is a parallelogram (rectangle or square) you know because the side AD is equal to BC and AB is equal to DC

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How do you do this equation? 9x+(y)i-5=-12+4

Vaselesa [24]

$9x+yi-5=-12+4\\\\(9x-5)+yi=-13\iff9x-5=-13\ and\ y=0\\\\9x=-13+5\\9x=-8\\x=-\frac{8}{9}\\\\Answer:x=-\frac{8}{9}\ and\ y=0.$

3 0

2 years ago

Please help need an answer by today

love history [14]

We don't know what the question is.

It could be "What is the selling price ?"
If that's the question, then . . .

Since the store marks up their cost by 60% before they sell
the thing, the price they sell it for is

(1.60 of their cost).

You know their cost. The selling price is (1.60 x $80) .

8 0

2 years ago

Sam scored 43, 48, and 42 points on three tests. How many points should he get on the fourth test to get an average score of 50?

tatiyna

So we know that an average is the sum of the scores divided by the number of scores that were added together. In this case we are going to be dealing with 4 tests. So let's say x is the score for our fourth test. We can create this equation:

$\frac{x+43+48+42}{4}=50$

So then we need to simplify the top:

$\frac{x+133}{4}=50$

Then multiply by 4 on both sides to get rid of the denominator:

$x+133=200$

Then solve for x:

$x=67$

So now we know that Sam needs to score a 67 on the fourth test to have an average score of 50.

6 0

2 years ago

Read 2 more answers

Please help!!!

Nonamiya [84]

Answer:

I belive it would be 1/5. ;;;

4 0

2 years ago

A fruit stand has to decide what to charge for their produce. They need \$10$10 for 44 apples and 44 oranges. They also need \$1

KatRina [158]

Answer:

<em>We can't find a unique price for an apple and an orange.</em>

Step-by-step explanation:

Suppose, the price of an apple is $x$ and the price of an orange is $y$

They need $10 for 4 apples and 4 oranges. So, the first equation will be.......

$4x+4y=10 ........................................(1)$

They also need $15 for 6 apples and 6 oranges. So, the second equation will be........

$6x+6y= 15 ........................................(2)$

Dividing equation (1) by 2 on both sides : $2x+2y= 5$

Dividing equation (2) by 3 on both sides : $2x+2y=5$

So, we can see that both equation (1) and (2) are actually same. That means, we will not get any unique solution for $x$ and $y$ here. Both $x$ and $y$ have <u>"infinitely many solutions"</u>.

Thus, we can't find a unique price for an apple and an orange.

4 0

2 years ago