3 years ago

I only have limited time please help

Mathematics

1 answer:

belka [17]3 years ago

5 0

Answer:

b. 10

Step-by-step explanation:

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notka56 [123]

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<span>Replace denominators and resolve:
</span> $\frac{3+4x}{2} + \frac{5-x}{3} = \frac{29}{6}$
$\frac{3(3+4x)}{6} + \frac{2(5-x)}{6} = \frac{29}{6}$
Cancel the dominators
$\frac{3(3+4x)}{\diagup\!\!\!\!6} + \frac{2(5-x)}{\diagup\!\!\!\!6} = \frac{29}{\diagup\!\!\!\!6}$
$3(3+4x) + 2(5-x) = 29$
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$12x - 2x = 29 - 9 - 10$
$10x = 20 - 10$
$10x = 10$
$x = \frac{10}{10}$
$\boxed{\boxed{x = 1}}\end{array}}\qquad\quad\checkmark$

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