Answer:
Mary bought 9 Golden Delicious apples
Step-by-step explanation:
This can be solved by setting up a system of equations. Based on the information given, the equations would be set up as follows.
I prefer to solve using substitution, but elimination can be used as well
We can now plug in this g value to the first equation
This means mary bought 13 delicious apples. She bought 22 apples in total, so the total number minus the amount of delicious apples will give us the amount of golden delicious apples.
22 - 13 = g
9 = g
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To solve this equation by elimination, what you would do is multiply one of the equations by -1, or distribute -1 to each term in the equation, any of the 2 equations. Then align the equations and add them together.
-(X + 3y = 3)
-X - 3y = -3
-X - 3y = -3
X + 6y = 3
__________
3y = 0
y = 0/3 = 0.
Now we can solve for x, by simply plugging the value of y into any of the 2 equations.
X + 6y = 3
X + 6(0) = 3
X + 0 = 3
X = 3.
The solution to your system of equations would be (3,0).
Check this by plugging in the point to the other equation and see if it is true.
X + 3y = 3
(3) + 3(0) = 3
3 + 0 = 3
3 = 3.
Thus it is the solution.
Answer: Hello!
A second order differential equation has the next shape:
where p(t), q(t) and g(t) are functions of t, that can be constant numbers for example.
And is called homogeneus when g(t) = 0, so you have:
Then a second order differential equation is homogeneus ef every term involve either y or the derivatives of y.
First find slope
5-10/-1-0= 5
find y-intercept
10=5(0)+B
b=-10
equation: y=5x-10
Answer:
x=23°; θ=87°
Step-by-step explanation:
These two angles create what is known as supplementary angles, or 2 angles that add up to 180°. We know this because all horizontal lines are 180° on either side. Since we know the total value of these two angles should equate to 180°, we can set up a simple equation:
Now, using algebra, we can solve for x:
Plugging x back into the equation, we get:
Therefore, the total angle is equal to 87° and x is equal to 23°.
Hope this helps!
