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eimsori [14]
3 years ago
5

How many moles of solute are present in 2 L of a 25M potassium nitrate (KNO3) solution?

Chemistry
1 answer:
Maksim231197 [3]3 years ago
8 0
Mole= Molarity. Volume(L) = (25)(2)= 50 moles
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If a cell wants to tell another cell what to do, it will send the message through
horsena [70]

Answer:

it will send the message through the axon

6 0
3 years ago
How many are molecules ( or formula) in each sample?
andre [41]

Answer:

  • 4.010 \times 10^{25} \text { molecules of } \mathrm{NaHCO}_{3} \text { present in } 55.93 \mathrm{kg} \text { of } \mathrm{NaHCO}_{3}
  • 16.86 \times 10^{26} \text { molecules of } \mathrm{Na}_{3} \mathrm{PO}_{4} \text { present in } 459 \mathrm{kg}\left(4.59 \times 10^{5} \mathrm{gm}\right) \text { of } \mathrm{Na}_{3} \mathrm{PO}_{4}

<u>Explanation</u>:

<u>Number of molecules for 55.93 \mathrm{kg} \text { of } \mathrm{NaHCO}_{3}</u>

\text { Firstly molar mass is calculated of } \mathrm{NaHCO}_{3}:

Atomic mass of Na + H + C + 3(O)  = 22.99 + 1.008 + 12.01 + 3 × 16.00 = 84.00 g/mol

\text { Number of molecules of } \mathrm{NaHCO}_{3} \text { in } 55.93 \text { kg are as follows: }

55.93 \times\left(10^{3} \mathrm{gm}\right) \times \frac{1 \mathrm{mol} \mathrm{NaHCO}_{3}}{84.00 \mathrm{gm} \mathrm{NaHCO}_{3}} \times\left(6.022 \times 10^{23} \mathrm{molecules} \text { i.e Avogadro number }\right)

=4.010 \times 10^{26} \text { molecules of } \mathrm{NaHCO}_{3} \text { present in } 55.93 \mathrm{kg} \text { of } \mathrm{NaHCO}_{3}

<u>Number of molecules for for \left(4.59 \times 10^{5} \mathrm{gm}\right) \text { of } \mathrm{Na}_{3} \mathrm{PO}_{4}</u>

\text { Firstly molar mass is calculated of } \mathrm{Na}_{3} \mathrm{PO}_{4}

= Atomic mass of 3(Na) + P + 4(O)

= 3(22.99) + 30.97 + 4(16.00) = 163.94 g/mol

459 \times\left(10^{3} \mathrm{gm}\right) \times \frac{1 \mathrm{mol} N a_{3} P O_{4}}{163.94 \mathrm{gm} N a_{3} P O_{4}} \times\left(6.022 \times 10^{23} \mathrm{molecules} \text { i.e Avogadro number) } / 1 \mathrm{mol}\right.

=16.86 \times 10^{26} \text { molecules of } \mathrm{Na}_{3} \mathrm{PO}_{4} \text { present in } 459 \mathrm{kg}\left(4.59 \times 10^{5} \mathrm{gm}\right) \text { of } \mathrm{Na}_{3} \mathrm{PO}_{4}

8 0
3 years ago
Put the following metric units in order from largest to smallest pL, mL, dL, kL
earnstyle [38]

Answer:

kL, dL, mL, pL

Explanation:

pL stands for picoliters. This is equal to 1 × 10⁻¹² (0.000000000001) liters.

mL stands for milliliters. This is equal to 1 × 10⁻³ (0.001) liters.

dL stands for deciliters. This is equal to 1 × 10⁻¹ (0.1) liters.

kL stands for kiloliters. This is equal to 1 × 10³ (1000) liters.

8 0
3 years ago
Combustion of coal releases sulfur dioxide into the atmosphere. The following process converts this gas into sulfuric acid, a co
Usimov [2.4K]

Answer:

m=7.07gH_{2}SO_{4}

Explanation:

1. Take in account the sulfuric acid at STP:

1840\frac{g}{L}

2. Density is expressed as the ratio between the mass and the volume of a substance so:

d=\frac{m}{V}

Solving for m:

m=\frac{V}{d}

3. Replace values:

m=\frac{1.30*10^{4}L}{1840\frac{g}{L}}

m=7.07gH_{2}SO_{4}

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3 years ago
In a cold pack, which type of reaction draws heat from the surroundings?
Bingel [31]
That would be an endothermic reaction! :)
6 0
3 years ago
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