It stays roughly the same size. Electrons have a barely imperceptible mass so the overall mass of the atom is changed very little.
Answer:
The answer to your question is: Excess oxygen = 2.3 mol
Explanation:
Data
ZnS = 5 mol
O2 = 9.8 mol
Excess reactant = ?
Balanced reaction
2ZnS(s) + 3O2(g) → 2ZnO(s) + 2SO2(g)
MW ZnS = 65 + 32 = 97 x 2 = 194 g
MW O2 = 16 x 6 = 96 g
2 mol of ZnS ------------------- 3 mol O2
Ratio from the reaction = 3 mol O2/ 2 mol ZnS
= 1.5
Ratio from the quantities in the experiment = 9.8 mol O2 / 5 mol of ZnS
= 1.96
Excess reactant = Oxygen because the ratio increases
2 mol of ZnS ------------------- 3 mol O2
5 mol of ZnS ------------------- x
x = (5 x 3) / 2
x = 7.5 mol of O2
Excess Oxygen = 9.8 mol - 7.5 mol
Excess oxygen = 2.3 mol
Answer:
3.5 mL
Explanation:
Let us represent lauric acid with the symbol LaCOOH and the anion as LaCOO-. The reaction between the anion and H2SO4 is;
LaCOO-(aq) + H2SO4(aq) -----> LaCOOH(aq) + HSO4-(aq)
Number of moles of LaCOO- = 2.75 g/200 g/mol = 0.014 moles
Since the mole ratio of the reaction is 1:1, then the amount of H2SO4 required is also 0.014 moles
Then;
n = CV
n = number of moles
C= concentration
V = volume
V = n/C
V = 0.014 moles/4.0 M
V= 3.5 * 10^-3 L
V = 3.5 mL
Answer:
There are more nutrients available in estuaries. There are more nutrients available in estuaries.
Explanation:
Answer:
The density is 0, 61 g/cm3
Explanation:
We calculate the density:
Density= mass/volume = 3,8 g/6, 28 cm3 = 0, 61 g/cm3