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2 years ago

Graph that has a finite or limited number of data points

1 answer:

6 0

My answer -

It seems that you have missed the necessary options for this question, but anyway here is the answer. A graph that has a finite or limited number of data points is called a DISCRETE GRAPH. On the other hand, the opposite for this graph is called the continuous graph.

P.s

Happy to help you have an AWESOME!!!! day ^-^

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Evaluate the following a) 4!= b) 0!= c) 2! + 3!= d) 3! x 4! e) 10! / 7!

IRISSAK [1]

Answer:

See below for answers and explanations

Step-by-step explanation:

4! = 4*3*2*1 = 24

0! = 1

2! + 3! = 2*1 + 3*2*1 = 2 + 6 = 8

3! * 4! = 3*2*1 * 4*3*2*1 = 6 * 24 = 144

10! / 7! = 10*9*8*7*6*5*4*3*2*1 / 7*6*5*4*3*2*1 = 10*9*8 / 1 = 720

6 0

2 years ago

Help me please !!!!!!!!!!!

Mkey [24]

Answer:

s=5

Step-by-step explanation:

As you can see, you have a whole block that is 20. Then you have another block that is broken down to 4 squares.

So....

4s=20

divide 4 to 4s

divide 4 by 20

so s=5

8 0

3 years ago

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The table below shows how much paint it takes to paint the walls of a house. A 2-column table with 4 rows. Column 1 is labeled P

algol [13]

Answer:

the answer is c,Yes, because the ratios for each input and output are equivalent.

Step-by-step explanation:

6 0

3 years ago

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What is an example of what property ?

vodomira [7]

Answer:

Distributive Property

Step-by-step explanation:

7 equals (3+4).

Therefore, 4*7 equals 4*(3+4).

By distributive property, this will equal (4*3) + (4*4)

8 0

3 years ago

The sphere below has a radius of 2.5 inches and an approximate volume of 65.42 cubic inches.

Stells [14]

Part a: The radius of the second sphere is 5 inches.

Part b: The volume of the second sphere is 523.33 in³

Part c; The radius of the third sphere is 1.875 inches.

Part d: The volume of the third sphere is 27.59 in³

Explanation:

Given that the radius of the sphere is 2.5 inches.

Part a: We need to determine the radius of the second sphere.

Given that the second sphere has twice the radius of the given sphere.

Radius of the second sphere = 2 × 2.5 = 5 inches

Thus, the radius of the second sphere is 5 inches.

Part b: we need to determine the volume of the second sphere.

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=5$ , we get,

$V=\frac{4}{3} (3.14)(125)$

$V=\frac{1580}{3}$

$V=523.3333 \ in^3$

Rounding off to two decimal places, we have,

$V=523.33 \ in^3$

Thus, the volume of the second sphere is 523.33 in³

Part c: We need to determine the radius of the third sphere

Given that the third sphere has a diameter that is three-fourths of the diameter of the given sphere.

Hence, we have,

Diameter of the third sphere = $\frac{3}{4} (5)=3.75$

Radius of the third sphere = $\frac{3.75}{2} =1.875$

Thus, the radius of the third sphere is 1.875 inches

Part d: We need to determine the volume of the third sphere

The formula to find the volume of the sphere is given by

$V=\frac{4}{3} \pi r^3$

Substituting $\pi=3.14$ and $r=1.875$ , we get,

$V=\frac{4}{3} (3.14)(1.875)^3$

$V=\frac{4}{3} (3.14)(6.59)$

$V=27.5901 \ in^3$

Rounding off to two decimal places, we have,

$V=27.59 \ in^3$

Thus, the volume of the third sphere is 27.59 in³

4 0

3 years ago