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amid [387]
3 years ago
9

What happens when hydrogen gas is passed over hot ferric oxide plzz help ​

Chemistry
1 answer:
Rom4ik [11]3 years ago
3 0

When hydrogen is passed over hot ferric oxide (FeO) hydrogen reacts with oxygen present in the compound and forms water (H2O) and pure Iron

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Using the following equation how many grams of water you would get from 886 g of glucose:
ankoles [38]

Answer:

531.6g

Explanation:

Total moles of glucose in this case is: 886/180= 4.922 (mole)

For every 1 mole glucose we get 6 mole water

-> Mole of water is: 4.922 * 6= 29.533 (mole)

weight of water is 18. Therefore, total weight of water that we will have from 886g of glucose are: 25.933*18= 531.6g

8 0
3 years ago
[Picture] Fuse the two elements together.
svet-max [94.6K]

K2SO4    MgSO4      Al2(SO4)3     Ge2(SO4)4

KNO3     Mg(NO3)2   Al(NO3)3       Ge(NO3)4

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4 0
3 years ago
The variables for part 1 of this experiment include the types of materials, used in the cup, the masses of these materials and t
iVinArrow [24]
So, first off let’s look at what an independent and dependent variable is.

an independent variable doesn’t change when other variables change, therefore making it alone and independent.

a dependent variable changes based on other variables.

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hope this helps!
8 0
3 years ago
Dierdra began writing a summary of the relationship between the first and second laws of thermodynamics.
Vika [28.1K]

the correct answer is B

7 0
2 years ago
Read 2 more answers
C) A standard cubic foot of natural gas carries with it about 1.1 x 106 J of energy. Natural gas currently costs about $16.25 pe
pochemuha

Answer:

67692.31 J

396811.337 J

Explanation:

(a) The cost of standard cubic foot of natural gas = $16.25

The energy related to standard cubic foot of natural gas = 1.1\times 10^{6}\ J

Thus, As according to the question,

$16.25 of natural gas have 1.1\times 10^{6}\ J of energy.

$1 of natural gas have \frac{1.1\times 10^{6}}{16.25}\ J of energy.

<u>The amount of energy = 67692.31 J</u>

(b) The cost of one short ton of coal = $56.45

The energy related to the short ton of coal = 2.24\times 10^{7}\ J

Thus, As according to the question,

$56.45 of coal have 2.24\times 10^{7}\ J of energy.

$1 of coal have \frac{2.24\times 10^{7}}{56.45}\ J of energy.

<u>The amount of energy = 396811.337 J</u>

<u></u>

6 0
3 years ago
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