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4 years ago

What mixture is it ?

Chemistry

1 answer:

joja [24]4 years ago

7 0

The mixture should be

Heterogeneous

Explanation:

Definition: Diverse in character or content.

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What mass of Al2(SO4)3 results from mixing 12.93 g of AlCl3 with 10.34 g of (NH4)2SO3 as shown with a 54.2% yield?

avanturin [10]

Mass of Al₂(SO₄)₃ : 4.822 g

<h3>Further explanation </h3>

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

Reaction

2AlCl₃ + 3(NH₄)₂SO₄⇒Al₂(SO₄)₃+ 6NH₄Cl

MW AlCl₃ :133,34 g/mol

MW (NH₄)₂SO₄ : 132,14 g/mol

MW Al₂(SO₄)₃ : 342,15 g/mol

mol AlCl₃

$\tt mol=\dfrac{12.93}{133.34}=0.097$

mol (NH₄)₂SO₄

$\tt mol=\dfrac{10.34}{132.14}=0.078$

Limitng reactants (ratio mol : coefficient = the smaller)

AlCl₃ : (NH₄)₂SO₄ =

$\tt \dfrac{0.097}{2}:\dfrac{0.078}{3}=0.0485:0.026$

(NH₄)₂SO₄ ⇒ limiting reactants

So mol Al₂(SO₄)₃ from (NH₄)₂SO₄

$\tt \dfrac{1}{3}\times 0.078=0.026$

mass Al₂(SO₄)₃

$\tt 0.026\times 342.15=8.896$

with 54.2% yield, the mass of Al₂(SO₄)₃

$\tt 0.542\times 8.896=4.822~g$

7 0

3 years ago

What three human body systems coordinate cause an arm to move

tia_tia [17]

(A) nervous, muscular, skeletal

8 0

3 years ago

What makes an atom a good conductor?

andrew-mc [135]

Very little electric force is required to cause electron flow in conductors. This is due to electrons called "free electrons", which exist in the atoms of conductors. "Free electrons" are electrons that are very weakly bonded to the atom. ... Metals such as copper, silver, and gold are good conductors.

Well, atoms are loosely bound and free to move through the material. Almost all, or just most, atoms will hold on to electrons very tightly and are insulators.

3 0

4 years ago

How many grams of sodium chromate, Na2CrO4, are needed to react completely with

JulsSmile [24]

Answer:

We need 27.0 grams of Na2CrO4 to react with 56.7 grams of AgNO3

Explanation:

Step 1: data given

Mass of silver nitrate AgNO3 = 56.7 grams

Molar mass AgNO3 = 169.87 g/mol

Molar mass of Na2CrO4 = 161.97 g/mol

Step 2: The balanced equation

2AgNO3 + Na2CrO4 → Ag2CrO4 + 2NaNO3

Step 3: Calculate moles AgNO3

Moles AgNO3 = mass AgNO3 / molar mass AgNO3

Moles AgNO3 = 56.7 grams / 169.87 g/mol

Moles AgNO3 = 0.334 moles

Step 4: Calculate moles Na2CrO4 moles needed

For 2 moles AgNO3 we need 1 mol Na2CrO4 to produce 1 mol Ag2CrO4 and 2 moles NaNO3

For 0.334 moles AgNO3 we need 0.334 / 2 = 0.167 moles Na2CrO4

Step 5: Calculate mass Na2CrO4

Mass Na2CrO4 = 0.167 moles * 161.97 g/mol

Mass Na2CrO4 = 27.0 grams

We need 27.0 grams of Na2CrO4 to react with 56.7 grams of AgNO3

8 0

3 years ago

Hydrogen gas and oxygen gas combine according to this reaction: 2H2(g]+O2(g]→2H2O(l]At STP, a chemist mixes 3.74 L of hydrogen g

zavuch27 [327]

Answer:

1.47 Liters of O₂ were reacted

Explanation:

The reaction is:

2H₂ (g) + O₂(g) → 2H₂O(l)

As we have the volume of hydrogen we need to work with denstiy to determine the moles that have reacted.

Density = mass / volume

Density . volume = mass → 0.071 g/L . 3.74L = 0.265 g

We determine the moles of H₂ → 0.265 g. 1mol/2g = 0.132 moles

In the reaction, ratio is 2:1. We make a rule of three:

2 moles of H₂ need 1 mol of O₂ to react

Then, 0.132 moles would need (0.132 .1)/2 = 0.066 moles of O₂

In order to determine the volume we need the oxygen's density but, we have to convert the mass to moles, firstly.

0.066 moles . 32 g/ 1mol = 2.12 g

Then oxygen's density = oxygen's mass / oxygen's volume

Oxygen's volume = oxygen's mass / oxygen's density

O₂ volume = 2.12 g / 1.43 g/L = 1.47 L

5 0

3 years ago

Read 2 more answers