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Alona [7]
3 years ago
9

Metals often form several cations with different charges. Cerium, for example, forms Ce3+ and Ce4+ ions, and thallium forms Tl+

and Tl3+ ions. Cerium and thallium ions react as follows: 2Ce4+(aq)+Tl+(aq)→2Ce3+(aq)+Tl3+(aq) This reaction is very slow and is thought to occur in a single elementary step. The reaction is catalyzed by the addition of Mn2+(aq) according to the following mechanism: Ce4+(aq)+Mn2+(aq)Ce4+(aq)+Mn3+(aq)Mn4+(aq)+Tl+(aq)→→ →Ce3+(aq)+Mn3+(aq)Ce3+(aq)+Mn4+(aq)Mn2+(aq)+Tl3+(aq) Part A What is the rate law for the uncatalyzed reaction?
Chemistry
2 answers:
Dmitry [639]3 years ago
6 0

Answer:

Rate law for the uncatalyzed reaction:

Rate = k[Ce^4+]^2[Tl]

Explanation: rate law shows the mathematical relationship by comparing the rate of reaction with the reactants concentration.

Rate law= k[reactantA][reactantB] .

Rate law can be used to derive an equation that shows a reactant as a function of time. Also, it can be use to calculate the rate of reaction from known concentration.

frez [133]3 years ago
3 0

Answer:

Rate of reaction= k [Ce^3+]^2 [Tl^3+]

Explanation:

Since the reaction is thought to occur in a single reaction step for the uncatalysed reaction, and the reaction equation is: 2Ce4+(aq)+Tl+(aq)→2Ce3+(aq)+Tl3+(aq)

Rate of reaction= k [Ce^3+]^2 [Tl^3+]

Note that the rate of reaction = rate of appearance of products or rate of disappearance of reactants as shown above.

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What is the name of the element with a valence electron configuration of 2s^22p^4
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How many chiral center have butaclamol​
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4 0
3 years ago
Using the following equation 5KNO2+2KMnO4+3H2SO4=5KNO3+2MnSO4+K2SO4+3H20. Starting with 2.47 grams of KNO2 and excess KMnO4 how
Aleonysh [2.5K]

Given equation : 5KNO_{2} + 2KMnO_{4} + 3H_{2}SO_{4}\rightarrow 5KNO_{3} + 2MnSO_{4} + K_{2}SO_{4} + 3H_{2}O

Given information = 2.47 grams KNO2 and excess KMnO4 and we need to find grams of water (H2O).

Since KMnO4 is in excess, so grams of water(H2O) can be calculated using grams of KNO2 with the help of stoichiometry.

To find grams of water(H2O) from grams of KNO2 , we need to follow three steps.

Step 1. Convert 2.47 grams of KNO2 to moles of KNO2.

Moles = \frac{grams}{molar mass}

Molar mass of KNO2 = 85.10 g/mol

Moles = 2.47 gram KNO2\times \frac{1 mol KNO2}{85.10 gram KNO2}

Moles = 0.0290 mol KNO2

Step 2. Convert moles of KNO2 to moles of H2O using mole ratio.

Mole ratio are the coefficient present in front of the compound in the balanced equation.

Mole ratio of KNO2 : H2O is 5 : 3 (5 coefficient of KNO2 and 3 coefficient of H2O)

0.0290 mol KNO2\times \frac{3 mol H2O}{5 mol KNO2}

Mole = 0.0174 mol H2O

Step 3. Convert mole of H2O to grams of H2O

Grams = Moles X molar mass

Molar mass of H2O = 18.00 g/mol

Grams = 0.0174 mol H2O\times \frac{18 g H2O}{1 mol H2O}

Grams of water = 0.313 grams H2O

Summary : The above three steps can also be done in a singe setup as shown below.

2.47 gram KNO2\times \frac{(1 mol KNO2)}{(85.10 gram KNO2)}\times \frac{(3 mol H2O)}{(5 mol KNO2)}\times \frac{(18.00 gram H2O)}{(1mol H2O)}

In the above setup similar units get cancelled out and we will get grams of H2O as 0.313 grams water (H2O)

8 0
4 years ago
A battery can provide a current of 4.60 A at 3.40 V for 2.50 hr. How much energy (in kJ) is produced? 1st attempt kJ Energy
Lunna [17]

Answer:

The energy produced equals 140.760 kJ

Explanation:

The relation between power, current and voltage is

Power=Current\times Voltage

Applying the given values in the relation above we get

Power=4.60\times 3.40=15.64W

Now Since Power=\frac{Energy}{Time}\\\\Energy=Power\times Time

Again applying the calculated values we get

Energy=15.64\times 2.50\times 3600=140760Joules=140.76kJ

4 0
4 years ago
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