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nikitadnepr [17]
3 years ago
8

Write the ions present in a solution of K2CO3. Express your answers as chemical formulas separated by a comma. Offset subscripts

and charges on each ion. nothing
Chemistry
1 answer:
meriva3 years ago
8 0

Answer:

K ^+ , CO3 ^2-

Explanation:

The compound is potassium trioxocarbonate(IV).

It contains cation (potassium ion) and acid radical ( trioxocarbonate (IV) ion).

Since K is in group 1 of the periodic table, it loses one electron to form ion i.e K^1. trioxocarbonate IV ion has a charge of 2-.and so the ions of the compound are as shown in the answer above.

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Mathematically, molarity is expressed as \frac{\text{mass of solute(g)}}{\text{gram molecular weight X Volume of solution (l)}}

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