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anyanavicka [17]
4 years ago
11

What factors affect the geometry of a molecule?

Chemistry
1 answer:
navik [9.2K]4 years ago
3 0
<span>The factors that affect the geometry of a molecule would be </span>the arrangement of electrons, but does not describe that arrangement. The “shape<span>” of a </span>molecule<span> is how the outside atoms are arranged around the central atom. The lone pairs of electrons </span>affect<span> this arrangement.</span>
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A chemist used 6.5 moles of water in this reaction. How many grams of water were used?
denpristay [2]

Answer:

\boxed {\boxed {\sf 120 \ or \ 117 \ grams \ H_2O \ depending \ on \ significant \ figures }}

Explanation:

We want to convert from moles of water to grams of water.

First, find the molar mass of water (H₂O) Look on the Periodic Table for the masses of hydrogen and oxygen.

  • Hydrogen (H): 1.008 g/mol
  • Oxygen (O): 15.999 g/mol

Next, add up the number of each element in water. The subscript of 2 comes after the H, so there are 2 moles of hydrogen.

  • 2 Hydrogen: (1.008 g/mol*2) = 2.016 g/mol

Finally, add the molar mass of 2 hydrogen and 1 oxygen.

  • 2.016 g/mol (2 Hydrogen) + 15.999 g/mol (1 oxygen)= 18.015 g/mol

Next, find the grams in 6.5 moles.

Use the molar mass we just found as a ratio.

molar \ mass \ ratio: \frac{18.015 \ g \ H_2O}{1 \ mol \ H_2O}

We want to find the grams in 6.5 moles. We can multiply the ratio above by 6.5

6.5 \ mol \ H_2O * \frac{18.015 \ g \ H_2O}{1 \ mol \ H_2O}

Multiply. Note that the moles of H₂O will cancel each other out.

6.5 * \frac{18.015 \ g \ H_2O}{1}

6.5 * {18.015 \ g \ H_2O}

117.0975 \ g \ H_2O

If we want to round to the technically correct significant figures, it would be 2 sig figs. The original measurement, 6.5, has 2 (6 and 5).

\approx 120 \ g \ H_2O

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Explanation:

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What happens when a pure substance undergoes a chemical change
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