Answer:
attached below is the required solution
Explanation:
A) Zinc acetate + Sodium carbonate
B) barium nitrate + sodium sulfate
C ) lead ( II ) nitrate + sodium sulfate
D) Zinc acetate + sodium sulfate
E) barium nitrate + potassium iodide
F) Lead ( I ) nitrate + potassium iodide
G) Zinc acetate + potassium iodide
Answer:
C4H10
Explanation:
Remark
Every periodic table is different. I'm going to use approximate numbers.
Emperical Formula Mass
2C = 2 * 12 = 24
H5 = 5 1 5
Emperical Formula Mass = 29
Solution
To get the molecular Molar Mass, you use
Molecular Molar Mass = number of mol of each constituent * empirical molar mass
Molecular mass = 58.14 rounded to 58
empirical mass = 29
moles = constitutent = ?
58 = 29 * mols constituent Divide by 29
2 = moles constituent
Answer
(C2H5)_2
C4H10
I think it's A and B but I'm not good at chem. I remember being asked a similar question and I believe this is correct.
<h3>
Answer:</h3>
2.26 × 10²⁴ atoms Zn
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
3.75 mol Zn (Zinc)
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- [DA] Set up:
- [DA] Multiply/Divide [Cancel out units]:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
2.25825 × 10²⁴ atoms Zn ≈ 2.26 × 10²⁴ atoms Zn
