<u>Answer:</u> The concentration of hydrogen gas at equilibrium is 0.0275 M
<u>Explanation:</u>
Molarity is calculated by using the equation:

Moles of HI = 0.550 moles
Volume of container = 2.00 L

For the given chemical equation:

<u>Initial:</u> 0.275
<u>At eqllm:</u> 0.275-2x x x
The expression of
for above equation follows:
![K_c=\frac{[H_2][I_2]}{[HI]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BH_2%5D%5BI_2%5D%7D%7B%5BHI%5D%5E2%7D)
We are given:

Putting values in above expression, we get:

Neglecting the negative value of 'x' because concentration cannot be negative
So, equilibrium concentration of hydrogen gas = x = 0.0275 M
Hence, the concentration of hydrogen gas at equilibrium is 0.0275 M
Answer:
You will have 19.9L of Cl2
Explanation:
We can solve this question using:
PV = nRT; V = nRT/P
<em>Where V is the volume of the gas</em>
<em>n the moles of Cl2</em>
<em>R is gas constant = 0.082atmL/molK</em>
<em>T is 273.15K assuming STP conditions</em>
<em>P is 1atm at STP</em>
The moles of 63g of Cl2 gas are -molar mass: 70.906g/mol:
63g * (1mol / 70.906g) = 0.8885 moles
Replacing:
V = 0.8885mol*0.082atmL/molK*273.15K/1atm
V = You will have 19.9L of Cl2
Molarity of solution is mathematically expressed as,
M =

We know that volume = mass/density
Given: mass of solution = 100 g, Density = 1.34 g/ml
∴ volume = 100/1.34 = 88.49 ml = 0.08849 l
Also, we know that molecular weight of sucrose = 342.3 g/mol
∴M =

= 6.979 M
Thus, molarity of solution is 6.979 M
Answer:
<u>Explanation</u>:
<u>Number of molecules for
</u>

Atomic mass of Na + H + C + 3(O) = 22.99 + 1.008 + 12.01 + 3 × 16.00 = 84.00 g/mol



<u>Number of molecules for for
</u>

= Atomic mass of 3(Na) + P + 4(O)
= 3(22.99) + 30.97 + 4(16.00) = 163.94 g/mol

