Hello!
<span>We have the following statement data:
</span>
Data:




<span>As the percentage is the mole fraction multiplied by 100:
</span>

<span>The mole fraction will be the percentage divided by 100, thus:
</span><span>What is the partial pressure of oxygen in this mixture?
</span>



<span>To calculate the partial pressure of the oxygen gas, it is enough to use the formula that involves the pressures (total and partial) and the fraction in quantity of matter:
</span>
In relation to

:




<span>
Answer:
</span><span>
b. 320.0 mm hg </span>
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density 15.4 grams per 1.2³ cm³ ≅ 8.9 grams per cm³
<span>Find the metal that has a density of approximately 8.9 g/cm³</span>
Explanation:
here's the answer to your question
In this problem Al metal is a limiting reactant as it is present in less amount as compared to chlorine gas, Hence, controls the formation of ALCl3. So, the amount of AlCl3 produced is 40.05 grams. Solution is as follow,