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lana66690 [7]
3 years ago
14

Consider the chemical equation for the production of water: 2 H2+O2→2 H2O. If 100 grams of oxygen gas are used, what would the p

ercent yield be if 75 g of H2O was produced? Show your work.
Chemistry
1 answer:
Cerrena [4.2K]3 years ago
4 0

Answer:

The percentage yield of water is 66.67%.

Explanation:

2H_2+O_2\rightarrow 2H_2O

Mass of oxygen gas = 100 g

Moles of oxygen gas = \frac{100 g}{32 g/mol}=3.125 mol

According to reaction, 1 mole of oxygen gives 2 moles of water, then 3.125 moles of oxygen will give:

\frac{2}{1}\times 3.125 mol=6.25 mol

Mass of 6.25 moles of water :

6.25 mol × 18 g/mol = 112.5 g

Theoretical yield of water = 112.5 g

Experimental yield of water = 75 g

Percentage yield :

=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

=\frac{75 g}{112.5 g}\times 100=66.67\%

The percentage yield of water is 66.67%.

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