Consider the chemical equation for the production of water: 2 H2+O2→2 H2O. If 100 grams of oxygen gas are used, what would the p
1 answer:
Answer:
The percentage yield of water is 66.67%.
Explanation:
Mass of oxygen gas = 100 g
Moles of oxygen gas =
According to reaction, 1 mole of oxygen gives 2 moles of water, then 3.125 moles of oxygen will give:
Mass of 6.25 moles of water :
6.25 mol × 18 g/mol = 112.5 g
Theoretical yield of water = 112.5 g
Experimental yield of water = 75 g
Percentage yield :
The percentage yield of water is 66.67%.
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Answer : The value of is, 0.34 V
Explanation :
Here, copper will undergo reduction reaction will get reduced. Zinc will undergo oxidation reaction and will get oxidized.
The oxidation-reduction half cell reaction will be,
Oxidation half reaction:
Reduction half reaction:
Oxidation reaction occurs at anode and reduction reaction occurs at cathode. That means, gold shows reduction and occurs at cathode and chromium shows oxidation and occurs at anode.
The overall balanced equation of the cell is,
To calculate the of the reaction, we use the equation:
Putting values in above equation, we get:
Hence, the value of is, 0.34 V
- E(Bonds broken) = 1371 kJ/mol reaction
- E(Bonds formed) = 1852 kJ/mol reaction
- ΔH = -481 kJ/mol.
- The reaction is exothermic.
2 H-H + O=O → 2 H-O-H
There are two moles of H-H bonds and one mole of O=O bonds in one mole of reactants. All of them will break in the reaction. That will absorb
- E(Bonds broken) = 2 × 436 + 499 = 1371 kJ/mol reaction.
- ΔH(Breaking bonds) = +1371 kJ/mol
Each mole of the reaction will form two moles of water molecules. Each mole of H₂O molecules have two moles O-H bonds. Two moles of the molecule will have four moles of O-H bonds. Forming all those bond will release
- E(Bonds formed) = 2 × 2 × 463 = 1852 kJ/mol reaction.
- ΔH(Forming bonds) = - 1852 kJ/mol
Heat of the reaction:
is negative. As a result, the reaction is exothermic.