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lana66690 [7]
3 years ago
14

Consider the chemical equation for the production of water: 2 H2+O2→2 H2O. If 100 grams of oxygen gas are used, what would the p

ercent yield be if 75 g of H2O was produced? Show your work.
Chemistry
1 answer:
Cerrena [4.2K]3 years ago
4 0

Answer:

The percentage yield of water is 66.67%.

Explanation:

2H_2+O_2\rightarrow 2H_2O

Mass of oxygen gas = 100 g

Moles of oxygen gas = \frac{100 g}{32 g/mol}=3.125 mol

According to reaction, 1 mole of oxygen gives 2 moles of water, then 3.125 moles of oxygen will give:

\frac{2}{1}\times 3.125 mol=6.25 mol

Mass of 6.25 moles of water :

6.25 mol × 18 g/mol = 112.5 g

Theoretical yield of water = 112.5 g

Experimental yield of water = 75 g

Percentage yield :

=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100

=\frac{75 g}{112.5 g}\times 100=66.67\%

The percentage yield of water is 66.67%.

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How many molecules would be in 2.5 moles of H2O.show work
Fantom [35]

Answer:

1.5x 10^24

Explanation:

for every 1 mol there are 6.02 x 10^23 molecules

2.5 mol x 6.02 x 10^23

-----------------

1 mol

5 0
3 years ago
For the Zn - Cu^2+ voltaic cell Zn(s) + Cu^2+(aq, 1M) + Cu(s) E degree _cell = 1.10 V Given that the standard reduction potentia
Fittoniya [83]

Answer : The value of E^o_{(Cu^{2+}/Cu)} is, 0.34 V

Explanation :

Here, copper will undergo reduction reaction will get reduced. Zinc will undergo oxidation reaction and will get oxidized.

The oxidation-reduction half cell reaction will be,

Oxidation half reaction:  Zn\rightarrow Zn^{2+}+2e^-

Reduction half reaction:  Cu^{2+}+2e^-\rightarrow Cu

Oxidation reaction occurs at anode and reduction reaction occurs at cathode. That means, gold shows reduction and occurs at cathode and chromium shows oxidation and occurs at anode.

The overall balanced equation of the cell is,

Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu

To calculate the E^o_{(Cu^{2+}/Cu)} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

E^o_{cell}=E^o_{(Cu^{2+}/Cu)}-E^o_{(Zn^{2+}/Zn)}

Putting values in above equation, we get:

1.10V=E^o_{(Cu^{2+}/Cu)}-(-0.76V)

E^o_{(Cu^{2+}/Cu)}=0.34V

Hence, the value of E^o_{(Cu^{2+}/Cu)} is, 0.34 V

8 0
3 years ago
Determine total H for bonds broken and formed, the overall change in H, and the final answer with units. Is it ENDOthermic or EX
Mrac [35]
  • E(Bonds broken) = 1371 kJ/mol reaction
  • E(Bonds formed) = 1852 kJ/mol reaction
  • ΔH = -481 kJ/mol.
  • The reaction is exothermic.
<h3>Explanation</h3>

2 H-H + O=O → 2 H-O-H

There are two moles of H-H bonds and one mole of O=O bonds in one mole of reactants. All of them will break in the reaction. That will absorb

  • E(Bonds broken) = 2 × 436 + 499 = 1371 kJ/mol reaction.
  • ΔH(Breaking bonds) = +1371 kJ/mol

Each mole of the reaction will form two moles of water molecules. Each mole of H₂O molecules have two moles O-H bonds. Two moles of the molecule will have four moles of O-H bonds. Forming all those bond will release

  • E(Bonds formed) = 2 × 2 × 463 = 1852 kJ/mol reaction.
  • ΔH(Forming bonds) = - 1852 kJ/mol

Heat of the reaction:

  • \Delta H_{\text{rxn}} = \Delta H(\text{Breaking bonds}) + \Delta H(\text{Forming bonds})\\\phantom{ \Delta H_{\text{rxn}}} = +1371 + (-1852) \\\phantom{ \Delta H_{\text{rxn}}} = -481 \; \text{kJ} / \text{mol}

\Delta H_{\text{rxn}} is negative. As a result, the reaction is exothermic.

3 0
3 years ago
Cobalt (Co) has an atomic mass of 59 and an atomic number of 27. Which statement correctly describes an atom of cobalt?
marysya [2.9K]

Answer:

A

Explanation:

27 us the number of protons when we subtract 27 from 59 it will be 32 because a mass number is the sum of proton and neutron but tell u more on the comment

3 0
3 years ago
What volume will 2.5 mol of a gas at STP occupy ?
kvv77 [185]

Answer:

56

Explanation:

1 mole of gas at STP occupies 22.4 L of the gas

2.5 mole of the gas at STP occupies 22.4×2.5 L of the gas

so 2.5 mole of the gas at STP occupies 56 L of the gas .

6 0
2 years ago
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