Question

How many moles of Ammonium Sulfate can be made from 30.0mol of NH3? 2NH3 + H2SO4 --> (NH4)2SO4

Answer 1

Answer: 15.0 moles of $(NH_4)_2SO_4$ are formed from  30.0 mol of $NH_3$

Explanation:

The balanced chemical reaction is :

$2NH_3+H_2SO_4\rightarrow (NH_4)_2SO_4$

According to stoichiometry :

2 moles of $NH_3$ give = 1 mole of $(NH_4)_2SO_4$

Thus 30.0 moles of $NH_3$ will give =$\frac{1}{2}\times 30.0=15.0moles$  of $(NH_4)_2SO_4$

Thus 15.0 moles of $(NH_4)_2SO_4$ are formed from  30.0 mol of $NH_3$