Answer:
The concentration of the solution is 1.364 molar.
Explanation:
Volume of perchloric acid = 29.1 mL
Mass of the solution = m
Density of the solution = 1.67 g/mL

Percentage of perchloric acid in 48.597 solution :70.5 %
Mass of perchloric acid in 48.597 solution :
= 
Moles of perchloric acid = 
In 29.1 mL of solution water is added and volume was changed to 250 mL.
So, volume of the final solution = 250 mL = 0.250 L (1 mL = 0.001 L)


The concentration of the solution is 1.364 molar.
Answer:
Molar absorptivity or molar extinction co-effecient = 2120.14 cm⁻¹M⁻¹
Explanation:
First convert Concentration from ppm inM or mol/l
⇒ Molar mass of KMnO₄ = 158.03 g
⇒ 4.48 ppm = 4.48 mg/l = 4.48 x 10⁻³ g/l
⇒ Molarity =
= 2.83 x 10⁻⁵ molar
Absorbance (A) = - log(T) ( T = % transmittance)
= - log(0.859)
= 0.06
According to Lambert Beer's law
ε = 
or, ε = 
or, ε = 2120.14 cm⁻¹M⁻¹
Where
ε = Molar absorptivity
A = absorbance
C = Molar concentration of KMnO₄ solution
l = length
Answer:
C₂ = 1.26 mol/dm³
Explanation:
Given data:
Volume of HCl =V₁ = 15.7 cm³
Volume of LiOH = V₂ = 25 cm³
Concentration of HCl =C₁ = 2 mol/dm³
Concentration of LiOH =C₂= ?
Solution:
Chemical equation:
LiOH + HCl → LiCl + H₂O
Formula:
C₁V₁ = C₂V₂
by putting values,
15.7 cm₃× 2 mol/dm³ = C₂× 25 cm³
C₂ = 15.7 cm₃× 2 mol/dm³ / 25 cm³
C₂ = 31.4 cm₃.mol/dm³ / 25 cm³
C₂ = 1.26 mol/dm³
B.
Isotopes is an atom has same number of electrons and protons but different number of neutron.