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Alekssandra [29.7K]
3 years ago
13

Cam is going to roll a fair 6-sided die 2,400 times. What is the best prediction for the number of times that cam will roll the

number 4?
Mathematics
2 answers:
mina [271]3 years ago
7 0

Answer:

Close to 400 times not exactly 400.

ivolga24 [154]3 years ago
4 0
It doesn’t matter how many times she rolls the dice. she will have a 1/6 chance is rolling the number 4, which is a 16.6% chance
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Please help!!!!! I’ll give you brainliest
Nikolay [14]

Answer:

A=32

B=3

C=7

Step-by-step explanation:

Caitlyn surveyed 100 students to find out their favorite class. There were 29 students who enjoyed biology and 35 students who enjoyed English. There were 12 students who did not enjoy Biology, English, or Math.

29 like Biology so to find B you subtract. 29-6-5=3

35 like English so to find C 35-3-5-20=7

Total of 100 students subtract what you know to find A.

100-15-6-5-3-7-20-12=32

6 0
3 years ago
How do you solve 1/2x x 3/5y=5
Anit [1.1K]
1/2 is a fraction so it is 5
8 0
2 years ago
Read 2 more answers
A wire of length 7x is bent into the shape of a square. Express the area A of the square as a function of z.
Nostrana [21]

7×

4+4+4+4

4+4=8

4+4=8

8+8=16

3 0
3 years ago
An elliptical-shaped path surrounds a garden, modeled by quantity x minus 20 end quantity squared over 169 plus quantity y minus
Margaret [11]

The <em>maximum</em> distance between any two points of the ellipse is 34 feet.

<h3>Procedure - Determination of the distance between two points of a ellipse</h3>

The maximum distance between any two points of a ellipse is the <em>maximum</em> distance between the ends of the ellipse along the <em>longest</em> axis, which is parallel to the y-axis in this case.

In addition, the equation of the ellipse in <em>standard</em> form is defined by this formula:

\frac{(x-h)^{2}}{a^{2}} + \frac{(y-k)^{2}}{b^{2}} = 1 (1)

Where:

  • h, k - Coordinates of the center of the ellipse.
  • a, b - Lengths of each semiaxis.

Hence, the maximum distance (d_{max}), in feet, is calculated by this formula:

d_{max} = 2\cdot b (2)

If we know that b = 17, then the maximum distance between any two points of the ellipse is:

d_{max} = 2\cdot (17\,ft)

d_{max} = 34\,ft

The <em>maximum</em> distance between any two points of the ellipse is 34 feet. \blacksquare

<h3>Remark</h3>

The statement is incomplete and poorly formatted, correct form is presented below:

<em>An elliptical-shaped path surrounds a garden, modeled by </em>\frac{(x-20)^{2}}{169} + \frac{(y-18)^{2}}{289} = 1<em>, where all measurements are in feet. What is the maximum distance between any two points of the path.</em>

To learn more on ellipses, we kindly invite to check this verified question: brainly.com/question/19507943

5 0
2 years ago
Can someone help me out please?
Furkat [3]

Answer:

h = √(44) ft

Step-by-step explanation:

Just looked back and A is actually the area because the unit was ft².

Area of a right isosceles triangle is half the area of a square.

A = ½S²

in this case your side is h.

A = ½h²

2A = h²

√(2A) = h

√(2(22)) = h

√(44) = h

plug that in your calculator for the answer.

4 0
3 years ago
Read 2 more answers
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