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Alekssandra [29.7K]
3 years ago
13

Cam is going to roll a fair 6-sided die 2,400 times. What is the best prediction for the number of times that cam will roll the

number 4?
Mathematics
2 answers:
mina [271]3 years ago
7 0

Answer:

Close to 400 times not exactly 400.

ivolga24 [154]3 years ago
4 0
It doesn’t matter how many times she rolls the dice. she will have a 1/6 chance is rolling the number 4, which is a 16.6% chance
You might be interested in
Q(x)=x^3+ax^2+2b is divided by (x-3) and has a remainder of 4. Find the values of "a" and "b"​
Sati [7]

Answer:

Let p(x) = x3 + ax2 + bx +6

(x-2) is a factor of the polynomial x3 + ax2 + b x +6

p(2) = 0                                                                                      

p(2) = 23 + a.22 + b.2 +6 =8+4a+2b+6 =14+ 4a+ 2b = 0

7 +2 a +b = 0

b = - 7 -2a -(i)                                                                              

x3 + ax2 + bx +6 when divided by (x-3) leaves remainder 3.

p(3) = 3                                                                                      

p(3) = 33 + a.32 + b.3 +6= 27+9a +3b +6 =33+9a+3b = 3

11+3a +b =1 => 3a+b =-10 => b= -10-3a -(ii)                                    

Equating the value of b from (ii) and (i) , we have

(- 7 -2a) = (-10 - 3a)

a = -3                                                                                          

Substituting a = -3 in (i), we get

b = - 7 -2(-3) = -7 + 6 = -1

Thus the values of a and b are -3 and -1 respectively.

Step-by-step explanation:

4 0
3 years ago
(3/2)^2÷(1-3/2+√(1/8+7/16))×(1+2/3)^3<br> ayudaaaaaaaa
hram777 [196]

Answer:

ayuda wala pa kmi SAP UMAYS

4 0
2 years ago
The probability that a randomly selected student is a girl is 0.52, and the probability that a student is a girl and in an art c
DaniilM [7]

Answer: The answer is 0.38

Step-by-step explanation:

Well, everything is given, as stated in the question "the probability that a student is a girl and in an art class is 0.20."

It's given that the probability that a student is a girl is 0.52.

However, in the question, it said that it's given a student is a girl.

You have the probability that a student is a girl and in art class, so you need to find what 0.52 was multiplied by which would be the probability of someone being in art class. Knowing this you can do 0.20 / 0.52 to get 0.38.

4 0
2 years ago
In a study of 420,095 Danish cell phone users, 135 subjects developed cancer of the brain or nervous system (based on data from
Maksim231197 [3]

Answer:

z=\frac{0.0003214 -0.00034}{\sqrt{\frac{0.00034(1-0.00034)}{420095}}}=-0.654  

p_v =2*P(Z  

So the p value obtained was a very high value and using the significance level given \alpha=0.005 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that the true proportion not differs significantly from the specified value of 0.00034 or 0.034%.

Step-by-step explanation:

1) Data given and notation  

n=420095 represent the random sample taken

X=135 represent the subjects developed cancer of the brain or nervous system (based on data from the Journal of the National Cancer Institute as reported in USA Today)

\hat p=\frac{135}{420095}=0.0003214 estimated proportion of subjects developed cancer of the brain or nervous system (based on data from the Journal of the National Cancer Institute as reported in USA Today)

p_o=0.00034 is the value that we want to test

\alpha=0.005 represent the significance level

Confidence=99.5% or 0.995

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the brain or nervous system at a rate that is different from the rate of 0.0340% :  

Null hypothesis:p=0.00034  

Alternative hypothesis:p \neq 0.00034  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.0003214 -0.00034}{\sqrt{\frac{0.00034(1-0.00034)}{420095}}}=-0.654  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.005. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z  

So the p value obtained was a very high value and using the significance level given \alpha=0.005 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that the true proportion not differs significantly from the specified value of 0.00034 or 0.034%.  

4 0
3 years ago
|j|=|2j+3| please help me
Softa [21]
Simplifying
j = (2j + 3)

Reorder the terms:
j = (3 + 2j)

Remove parenthesis around (3 + 2j)
j = 3 + 2j

Solving
j = 3 + 2j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-2j' to each side of the equation.
j + -2j = 3 + 2j + -2j

Combine like terms: j + -2j = -1j
-1j = 3 + 2j + -2j

Combine like terms: 2j + -2j = 0
-1j = 3 + 0
-1j = 3

Divide each side by '-1'.
j = -3

Simplifying
j = -3
8 0
3 years ago
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