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krok68 [10]
4 years ago
8

Watch the animation and identify the correct conditions for forming a hydrogen bond. check all that apply. check all that apply.

the ch4 molecule exhibits hydrogen bonding. hydrogen bonding occurs when a hydrogen atom is covalently bonded to an n, o, or f atom. a hydrogen bond is equivalent to a covalent bond. a hydrogen bond is possible with only certain hydrogen-containing compounds. a hydrogen atom acquires a partial positive charge when it is covalently bonded to an f atom.
Chemistry
2 answers:
OLga [1]4 years ago
6 0
The ch4 molecule exhibits hydrogen bonding.
This statement is false. A CH4 molecule do not have a hydrogen bonding instead it has dipole dipole attraction.

Hydrogen bonding occurs when a hydrogen atom is covalently bonded to an N, O, or F atom.
This would be a true statement. A hydrogen bond is present when an atom of hydrogen shares electrons with O, N or F atom.

A hydrogen bond is equivalent to a covalent bond.
This is a false statement. A hydrogen bond is an intermolecular force of attraction while covalent bond is a intramolecular force. So, they would mean different things.

a hydrogen bond is possible with only certain hydrogen-containing compounds.
This would be true. Without the presence of an hydrogen atom definitely there would be no hydrogen bond.

a hydrogen atom acquires a partial positive charge when it is covalently bonded to an f atom.
This would be true since a HF is a polar molecule.
kirill115 [55]4 years ago
4 0

The right answer is:

*Hydrogen bonding occurs when a hydrogen atom is covalently bonded to an N, O, or F atom.

*A hydrogen bond is possible with only certain hydrogen-containing compounds.

*A hydrogen atom acquires a partial positive charge when it is covalently bonded to an F atom.

<h3>Further explanation </h3>

Watch the animation and identify the correct conditions for forming a hydrogen bond. check all that apply..

This animation showing the transient hydrogen bonding between water molecules.Each water molecule (H2O) has two hydrogens and two lone pairs of electrons on the oxygen, therefore it can make up to four hydrogen bonds with neighbouring molecules.

  • Hydrogen bonding occurs when a hydrogen atom is covalently bonded to an N, O, or F atom.  It is true because hydrogen bond is present when hydrogen shares electrons with O, N or F atom
  • A hydrogen bond is possible with only certain hydrogen-containing compounds.  This is true
  • The CH4 molecule exhibits hydrogen bonding.  It is false because CH4 molecule do not have a hydrogen bonding instead it has dipole dipole attraction.
  • A hydrogen atom acquires a partial positive charge when it is covalently bonded to an F atom. This is true because  since a HF is a polar molecule
  • A hydrogen bond is equivalent to a covalent bond. It is false because a hydrogen bond is an intermolecular force of attraction whereas covalent bond is a intramolecular force.

<h3>Learn more</h3>
  1. Learn more about hydrogen bond brainly.com/question/11679211
  2. Learn more about covalent bond brainly.com/question/10473204
  3. Learn more about hydrogen-containing compounds brainly.com/question/2385919

<h3>Answer details</h3>

Grade:  9

Subject:  Chemistry

Chapter:  hydrogen bond

Keywords: hydrogen bond, covalent bond, hydrogen-containing compounds, partial positive charge, compounds

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3 years ago
Which of the following techniques can be used to separate a heterogeneous mixture into its component parts?
fredd [130]

Answer:

                  Separation by density

Explanation:

                    Mixtures are made up of two or more pure substances which tends to keep their individual identities. These components can be separated from each other by different physical techniques.

                    Mixtures are further classified as;

  (i)  Homogenous Mixture:

                                            In this type of the mixtures the components are uniformly mixed and their properties as well as composition as uniform throughout. Such mixtures are also called as solutions.

The physical methods used to separate these components from each other are distillation (taking heat and pressure into account), Solvent extraction, Magnetic separation, Chromatography e.t.c.

  (ii)  Homogenous Mixture:

                                            In this type of the mixtures the components are not uniformly mixed and their physical properties and composition are also not uniform.

The physical methods used to separate these components from each other are Filtration, Magnetic Separation, Centrifugation, Flotation e.t.c.

So, in given options the density can play role by settling the massive components of heterogenous mixture to sit at the bottom and separated

8 0
3 years ago
Read 2 more answers
I need help with the first question, if you can help with the other two I would really appreciate it!​
Lorico [155]

Answer:

5

Explanation:

6 0
3 years ago
1 question content area what is the total number of valence electrons in the lewis structure of sebr2o?
joja [24]

There are 24 valance electrons in the compound.

<h3>What are valence electrons?</h3>

We know that the valence electrons are those that are found on the valence shell of an atom. There are four atoms that can be seen in the compound that is under consideration. The atoms are selenium, bromine (2 atoms) and oxygen.

Given that there are seven valence electrons in bromine and six valence electrons in oxygen and selenium. We have;

2(7 electrons of bromine) + 6 electrons of oxygen + 4 electrons of Se

= 24 electrons

Learn more about valence electrons:brainly.com/question/8906371

#SPJ1

6 0
1 year ago
I NEED HELP PLEASE, THANKS! :)
marin [14]

Answer:

\large \boxed{1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2 }}

Explanation:

1. Calculate the moles of copper(II) hydroxide

\text{Moles of Cu(OH)}_{2} = \text{23.45 g Cu(OH)}_{2} \times \dfrac{\text{1 mol Cu(OH)}_{2}}{\text{97.562 g Cu(OH)}_{2}} = \\\\\text{0.240 36 mol Cu(OH)}_{2}

2. Calculate the molecules of copper(II) hydroxide

\text{No. of molecules} = \text{0.240 36 mol Cu(OH)}_{2} \times \dfrac{6.022 \times 10^{23}\text{ molecules Cu(OH)}_{2}}{\text{1 mol Cu(OH)}_{2}}\\\\= 1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2}\\\text{The sample contains $\large \boxed{\mathbf{1.447 \times 10^{23}}\textbf{ molecules Cu(OH)}_{\mathbf{2}}}$}

6 0
3 years ago
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