"CH3COOH + H2O CH3COO- + H3O+" is the equation among the choices given in the question <span>represents the reaction of acetic (ethanoic) acid with water. The correct option among all the options that are given in the question is the second option or option "B". I hope that the answer has helped you.</span>
Fixed density
Particles move smoothly
Answer:
Activation energy of phenylalanine-proline peptide is 66 kJ/mol.
Explanation:
According to Arrhenius equation- 
, where k is rate constant, A is pre-exponential factor, 
is activation energy, R is gas constant and T is temperature in kelvin scale.
As A is identical for both peptide therefore-
![\frac{k_{ala-pro}}{k_{phe-pro}}=e^\frac{[E_{a}^{phe-pro}-E_{a}^{ala-pro}]}{RT}](https://tex.z-dn.net/?f=%5Cfrac%7Bk_%7Bala-pro%7D%7D%7Bk_%7Bphe-pro%7D%7D%3De%5E%5Cfrac%7B%5BE_%7Ba%7D%5E%7Bphe-pro%7D-E_%7Ba%7D%5E%7Bala-pro%7D%5D%7D%7BRT%7D)
Here 
, T = 298 K , R = 8.314 J/(mol.K) and 
So, ![\frac{0.05}{0.005}=e^{\frac{[E_{a}^{phe-pro}-(60000J/mol)]}{8.314J.mol^{-1}.K^{-1}\times 298K}}](https://tex.z-dn.net/?f=%5Cfrac%7B0.05%7D%7B0.005%7D%3De%5E%7B%5Cfrac%7B%5BE_%7Ba%7D%5E%7Bphe-pro%7D-%2860000J%2Fmol%29%5D%7D%7B8.314J.mol%5E%7B-1%7D.K%5E%7B-1%7D%5Ctimes%20298K%7D%7D)
(rounded off to two significant digit)
So, activation energy of phenylalanine-proline peptide is 66 kJ/mol
As the gas is heated, the particles will begin to move faster. Likewise if you start to cool a gas, the particles will move slower. Because the gas remains at a constant pressure and volume, the particles cannot spread out so they simply move around the container even faster.
Hope this helps :)
Explanation:
Since methane gas is at 1 atm and 273 K, it is at standard temperature and pressure(STP).
One mole of every gas occupies 22.4 dm^3 at STP, and vice versa. So,
22.4 dm^3 at STP of CH4=1 mol=12+4(1)=16 g
0.462 L(0.462 dm^3) at STP of CH4
=(16 g×0.462 dm^3)/22.4 dm^3
=0.33 g
