Answer:
T₁ = 39 K
Explanation:
Given data:
Initial pressure = 1023.6 kpa
Final pressure = 8114 kpa
Final temperature = 36°C (36+ 273= 309K)
Initial temperature = ?
Solution:
P₁/T₁ = P₂/T₂
T₁ = P₁×T₂ /P₂
T₁ = 1023.6 kpa × 309 K /8114 kpa
T₁ = 316292.4 K. Kpa /8114 kpa
T₁ = 39 K
Thus original pressure was 39 k.
The signs of ΔS° and ΔH° will be negative.
A combustion reaction is a reaction in which a substance reacts with oxygen gas, releasing energy in the form of light and heat.
Combustion reactions must involve O2 as one reactant.
Consider the combustion of butane gas:
C₄H₁₀(g ) + 13/2O₂(g) → 4CO₂(g) + 5H₂O(g)
4 + 13/2 4 + 5
10.5 mol -------------> 9 mol
As the number of moles decreases entropy will decrease
so ΔS° = negative
since this example for combustion reaction heat is released (exothermic)
so ΔH° = negative.
Learn more about ΔS° here:
brainly.com/question/3784176
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K = 0.058 yr (constant)
Fraction of the pesticide = 36 years/12 = 3 half-lives , so around 1/8 left
when 99.9 % decomposed, 0.1 % is left , so the fraction is 0.001. To reach this point, it will take around +/- 120 years
Answer:
please give me BRAINLIEST answer
Explanation:
Answer.
Electron is not present in the nucleus of an atom. It revolves around the nucleus in orbit.
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