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boyakko [2]
3 years ago
11

What signs of a chemical reaction did you observe during the lab? Check all that apply.

Chemistry
2 answers:
Soloha48 [4]3 years ago
6 0

Answer:

1, 4, 5

Explanation:

1 - Color Change

4 - Formation of Gas

5 - Formation of Solid

(correct on ed)

max2010maxim [7]3 years ago
4 0
Color change
formation of a gas
formation of a solid
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Quick help I really need help
Sauron [17]

Answer:

CO2 H2o

Explanation:

8 0
3 years ago
B) Quelle est la masse de tétraoxyde de trifer (Fe3O4) produite si 3,60 moles de trioxyde de
hram777 [196]

Answer:

626,4 g de Fe₃O₄

Explanation:

Nous commencerons par écrire l'équation équilibrée de la réaction entre le fer (Fe) et le trioxyde d'aluminium. Ceci est donné ci-dessous:

9Fe + 4Al₂O₃ -> 3Fe₃O₄ + 8Al

De l'équation équilibrée ci-dessus,

4 moles d'Al₂O₃ ont réagi pour produire 3 moles de Fe₃O₄.

Par conséquent, 3,6 moles d'Al₂O₃ réagiront pour produire = (3,6 × 3) / 4 = 2,7 moles de Fe₃O₄

Ainsi, 2,7 moles de Fe₃O₄ sont produites à partir de la réaction.

Enfin, nous déterminerons la masse massique de Fe₃O₄ produite par la réaction. Ceci peut être obtenu comme suit:

Mole de Fe₃O₄ = 2,7 moles

Masse molaire de Fe₃O₄ = (3 × 56) + (4 × 16)

= 168 + 64

= 232 g / mol

Masse de Fe₃O₄ =?

Mole = masse / masse molaire

2,7 = Masse de Fe₃O₄ / 232

Croiser multiplier

Masse de Fe₃O₄ = 2,7 × 232

Masse de Fe₃O₄ = 626,4 g

Par conséquent, 626,4 g de Fe₃O₄ sont produits à partir de la réaction

7 0
2 years ago
What is the ionic charge for the calcium ion in CaCO3?
Lunna [17]
<span>The ionic charge of Calcium (Ca) in calcium carbonate (CaCO3) is 2+. CaCO3 has a neutral ionic charge sin CO3 has a 2- charge.</span>
3 0
3 years ago
If a 8 N force acts on a 4kg object, what is the resulting acceleration
cluponka [151]
The answer is 2 because you have to divide these numbers.<span />
7 0
3 years ago
Determine the concentration of H+ in each solution at 25∘C
puteri [66]

Answer:

1: [H+] = 0.01 M

2: [H+] = 0.0001 M

3: [H+] = 0.0001 M

Explanation:

Step 1: data given

pH = -log[H+]

pH = pOH = 14

Step 2:

1. A solution with pH = 2.0

pH = 2

-log[H+] = 2.0

[H+] = 10^-2

[H+] = 0.01 M

2. A solution with pH = 4.0

pH = 4

-log[H+] = 4.0

[H+] = 10^-4

[H+] = 0.0001 M

3. A solution with pOH = 10.0

pH = = 14 - 10 = 4

pH = 4

-log[H+] = 4.0

[H+] = 10^-4

[H+] = 0.0001 M

4 0
3 years ago
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