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jonny [76]
3 years ago
9

How many grams of water are needed to form 21.8 grams of oxygen gas?

Chemistry
1 answer:
GaryK [48]3 years ago
5 0

Answer:

24.5g

Explanation:

Given parameters:

Mass of oxygen gas = 21.8g

Unknown:

Mass of water  = ?

Solution:

This problem deals with the decomposition of water;

    Reaction equation;

                  2H₂O →  2H₂  +  O₂

2 mole of water will produce 1 mole of oxygen gas

First find the number of mole of the oxygen gas given;

          Number of moles  = \frac{mass}{molar mass}

    molar mass of O₂   = 2(16) = 32g/mol

 

  Number of moles of O₂  = \frac{21.8}{32}   = 0.68moles

 

    1 mole of oxygen gas will be produced from 2 mole of water

     0.68moles of oxygen gas will be produce from  0.68 x 2 moles of water;   = 1.36moles of water

Mass of water = number of moles x molar mass

  Molar mass of water = 2(1) + 16  = 18g/mol

Mass of water  = 1.36 x 18  = 24.5g

           

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Answer:

b) Baking soda

Explanation:

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Thus, baking soda is a base because it increases the concentration of hydroxide ions in water.

<em>Water</em> is <em>neutral</em>.

<em>Lemon juice</em> is an <em>acid</em> because it contains citric acid.

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The test that can be carried out is to place a small ours of Thorium in front of a phosphorescent screen and see if it has flashes, with the amount of them we can determine the amount of particle emitted per unit of time.

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In conclusion with the characteristics of the α and β particles we can find the design of an experiment to measure the ²³⁴Th particles is:

  • On a screen, measure the emission as a function of distance and when the value reaches a constant, there is the β particle emission from ²³⁴Th.
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Learn more about radioactive emission here: brainly.com/question/15176980

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