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jonny [76]
2 years ago
9

How many grams of water are needed to form 21.8 grams of oxygen gas?

Chemistry
1 answer:
GaryK [48]2 years ago
5 0

Answer:

24.5g

Explanation:

Given parameters:

Mass of oxygen gas = 21.8g

Unknown:

Mass of water  = ?

Solution:

This problem deals with the decomposition of water;

    Reaction equation;

                  2H₂O →  2H₂  +  O₂

2 mole of water will produce 1 mole of oxygen gas

First find the number of mole of the oxygen gas given;

          Number of moles  = \frac{mass}{molar mass}

    molar mass of O₂   = 2(16) = 32g/mol

 

  Number of moles of O₂  = \frac{21.8}{32}   = 0.68moles

 

    1 mole of oxygen gas will be produced from 2 mole of water

     0.68moles of oxygen gas will be produce from  0.68 x 2 moles of water;   = 1.36moles of water

Mass of water = number of moles x molar mass

  Molar mass of water = 2(1) + 16  = 18g/mol

Mass of water  = 1.36 x 18  = 24.5g

           

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Answer:

ΔS surrounding (entropy change of the reservoir) = -1 J/K

Explanation:

Given:

Change in heat (ΔH) = 150 joules

Temperature (T) = 150 K

Find:

ΔS surrounding (entropy change of the reservoir)

Computation:

ΔS surrounding (entropy change of the reservoir) = - ΔH / T

ΔS surrounding (entropy change of the reservoir) = - 150 / 150

ΔS surrounding (entropy change of the reservoir) = -1 J/K

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Answer:

The role that chlorine atoms have in increasing the depeltion rate ozone is that Cl acts as a catalyst.

Explanation:

  • From the two steps of the reaction:
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  2. ClO· + O → Cl· + O₂
  • The overall reaction is: O₃ + O → 2O₂
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8 0
3 years ago
Which substance can not be decomposed by a chemical change?
just olya [345]
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Answer:

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hope this helps

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3 years ago
AT constant temperature, a gas is compressed from 5.5 L to 1 L. At 1 L, the pressure of the gas is 98.2 kPa. What was the origin
svet-max [94.6K]

We have that  the original pressure of this gas  is mathematically given as

P2=17.854 kPa

<h3>Boyle's law</h3>

Question Parameters:

AT constant temperature, a gas is compressed from 5.5 L to 1 L.

At 1 L, the pressure of the gas is 98.2 kPa

Generally the equation for Boyle's law   is mathematically given as

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P2=17.854 kPa

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