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3 years ago

A certain material has a mass of 565 g while occupying 50 cm3 of space. what is this material?

1 answer:

5 0

<span>the material is Lead (Pb) .

you can get it by this steps:

1) first, we need to find the density:

when the denisty formula is = mass/volume.

and when we have the mass = 565 g, and volume is 50 Cm^3 . so, by

substitution: denisty = 565 g / 50Cm^3 = 11.3 g /Cm^3 . then after we get the

density of the material, we can look at the periodic table and serach for the

denisty which match the density result and find the element matching that

denisty. so our material here is lead as the denisty of lead is 11.34 g/Cm^3.</span>

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A tank of 0.1m3 volume contains air at 25∘C and 101.33 kPa. The tank is connected to a compressed-air line which supplies air at

Dmitriy789 [7]

Answer:

Amount of Energy = 23,467.9278J

Explanation:

Given

Cv = 5/2R

Cp = 7/2R wjere R = Boltzmann constant = 8.314

The energy balance in the tank is given as

∆U = Q + W

According to the first law of thermodynamics

In the question, it can be observed that the volume of the reactor is unaltered

So, dV = W = 0.

The Internal energy to keep the tank's constant temperature is given as

∆U = Cv((45°C) - (25°C))

∆U = Cv((45 + 273) - (25 + 273))

∆U = Cv(20)

∆U = 5/2 * 8.314 * 20

∆U = 415.7 J/mol

Before calculating the heat loss of the tank, we must first calculate the amount of moles of gas that entered the tank where P1 = 101.33 kPa

The Initial mole is calculated as

(P * V)/(R * T)

Where P = P1 = 101.33kPa = 101330Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

So, n = (101330 * 0.1)/(8.314*298)

n = 4.089891232222

n = 4.089

Then we Calculate the final moles at P2 = 1500kPa = 1500000Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

n = (1500000 * 0.1)/(8.314*298)

n = 60.54314465936812

n = 60.543

So, tue moles that entered the tank is ∆n

∆n = 60.543 - 4.089

∆n = 56.454

Amount of Energy is then calculated as:(∆n)(U)

Q = 415.7 * 56.454

Q = 23,467.9278J

3 0

3 years ago

10 points

djyliett [7]

Since the question is incomplete, the table has been searched in order to comply with the question.

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7 0

3 years ago

Why don't noble gases bond?

Luba_88 [7]

<span>Their outer shells are filled So much that they don't need to bond or react with any other atoms.</span>

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3 years ago

A chemical equation is balanced when the number of each

Lelu [443]

Answer: Atom/element

Explanation: Since matter cannot be created or destroyed, the number of atoms has to be equal on both sides of the equation.

4 0

3 years ago

Enter the oxidation number of one atom of each element in each reactant and product.

Anton [14]

Answer:

1. -4

2. +1

3. 0

4. +4

5. -2

6. +1

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reduced = H

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Know oxidation rules.

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7 0

3 years ago