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Hatshy [7]
3 years ago
5

Is the binomial a factor of the polynomial function?

Mathematics
2 answers:
Nady [450]3 years ago
5 0

Answer:

1.No

2.No

3.yes

4.No

5.No

ipn [44]3 years ago
3 0

To check if the binomial is a factor, we take it in the form of x – c = 0 and then x = c, then substitute the value of c into x on the polynomial equation. It is only a factor when the value of f(x) = 0

 

a. x – 1

x = 1

Substitute x = 1 into the equation.

f(x) = 1^3 + 3 * 1^2 – 25 * 1 – 75

f(x) = -96

(not a factor)

 

b. x – 3

x = 3

Substitute x = 3 into the equation.

f(x) = 3^3 + 3 * 3^2 – 25 * 3 – 75

f(x) = -96

(not a factor)

 

c. x + 3

x = -3

Substitute x = 3 into the equation.

f(x) = (-3)^3 + 3 * (-3)^2 – 25 * (-3) – 75

f(x) = 0

(a factor)

 

d. x - 5

x = 5

Substitute x = 3 into the equation.

f(x) = 5^3 + 3 * 5^2 – 25 * 5 – 75

f(x) = 0

(a factor)

 

e. x + 5

x = - 5

Substitute x = 3 into the equation.

f(x) = (-5)^3 + 3 * (-5)^2 – 25 * (-5) – 75

f(x) = 0

(a factor)

 

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1. Input
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Answer:

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Step-by-step explanation:

7 0
3 years ago
Suppose that at a state college, a random sample of 41 students is drawn, and each of the 41 students in the sample is asked to
ra1l [238]

Answer:

The  confidence interval for 90% confidence would be narrower than the 95% confidence

Step-by-step explanation:

From the question we are told that

  The  sample size is n = 41

   

For a 95% confidence the level of significance is  \alpha  = [100 - 95]\% =  0.05 and

the critical value  of  \frac{\alpha }{2}  is   Z_{\frac{\alpha }{2} } =Z_{\frac{0.05 }{2} }=  1.96

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the critical value  of  \frac{\alpha }{2}  is   Z_{\frac{\alpha }{2} } =Z_{\frac{0.10 }{2} }=  1.645

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given that other values are constant and only Z_{\frac{\alpha }{2} } is varying we have that

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  The  confidence interval is mathematically represented as

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Now looking at the above formula and information that we have deduced so far we can infer that as the confidence level reduces , the critical value  reduces, the margin of error  reduces and the confidence interval becomes narrower

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