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PSYCHO15rus [73]
3 years ago
15

How to find the surface area of a trapezoid

Mathematics
2 answers:
FinnZ [79.3K]3 years ago
7 0

This is the formula for finding the area of a trapezoid

kotykmax [81]3 years ago
6 0
To find the area of a trapezoid, start by adding together the length of the bases, which are the 2 sides of the trapezoid that are parallel with each other. Then, multiply that number by the height of the trapezoid. Finish by dividing the product by 2 to find the area.

A=a+b
2h
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Simplify the rational expression. State any restrictions on the variable n^4-11n^2+30/ n^4-7n^2+10
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To factor both numerator and denominator in this rational expression we are going to substitute n^{2} with x; so n^{2} =x and n ^{4} =  x^{2}. This way we can rewrite the expression as follows:
\frac{n^{4}-11n^{2} +30 }{n^{2}-7n^{2} +10 } =  \frac{ x^{2} -11x+30}{ x^{2} -7x+10}
Now we have two much easier to factor expressions of the form a x^{2} +bx+c. For the numerator we need to find two numbers whose product is c (30) and its sum b (-11); those numbers are -5 and -6. (-5)(-6)=30 and -5-6=-11.
Similarly, for the denominator those numbers are -2 and -5. (-2)(-5)=10 and -2-5=-7. Now we can factor both numerator and denominator:
\frac{ x^{2} -11x+30}{ x^{2} -7x+10} = \frac{(x-6)(x-5)}{(x-2)(x-5)}
Notice that we have (x-5) in both numerator and denominator, so we can cancel those out:
\frac{x-6}{x-2}
But remember than x= n^{2}, so lets replace that to get back to our original variable:
\frac{n^{2}-6 }{n^{2}-2 }
Last but not least, the denominator of rational expression can't be zero, so the only restriction in the variable is n^{2} -2 \neq 0
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Answer:

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Step-by-step explanation:

"Triple" denotes multiplication by 3.  Thus, the common factor here is 3.

The general formula for a geometric series is a(n) = a(1)(r)^(n-1), where a(1) is the first term, r is the common ratio.

Here, we have a(n)= (-12)(3)^(n-1) = -972.

We need to solve this for n, which represents the last term.

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