Find -sqrt(36 O t6 O -6 O 6 O 18

Tema [17]

Answer: m=20

Step-by-step explanation:

7 0

2 years ago

omar will donate up to $500 to charity. the money will be divided between two charities: the city of youth fund and educational

marshall27 [118]

Answer:

Please refer to the attached graph

Step-by-step explanation:

Knowing the following:

X = amount of money donated to the city youth fund

Y = amount of money donated to the educational growth foundation

We can write the statements in form of equations:

"Will donate up to $500, the money will be divided between two charities"

(a) $X + Y = \$ 500$

"The amount donated to the educational growth foundation to be at least four times the amount donated to the city youth fund"

(b) $Y \geq 4X$

If we graph both equations we can see the area where both conditions are met (see graph attached)

Where the blue line is (a) and the red line is (b)

Shaded area represent all the possible solutions for the donations, for example:

X=100 and Y=400 or

X=50 and Y=200, etc.

6 0

2 years ago

Which two integers is 42 between? -8 and -7 -5 and -4 -7 and -6 -9 and -8

Karo-lina-s [1.5K]

Answer:

6 and 7

Step-by-step explanation:

we know that 42 will lie between 36 and 49

And 36=6; 49=7

so we can be sure that 42 lies between 6 and 7

3 0

3 years ago

A jumbo crayon is composed of a cylinder with a conical tip. The cylinder is 12 cm tall with a radius of 1.5 cm, and the cone ha

s2008m [1.1K]

Answer:

Part 1) The lateral area of the cone is $LA=2\pi\ cm^{2}$

Part 2) The lateral surface area of the cylinder is $LA=36\pi\ cm^{2}$

Part 3) The surface area of the crayon is $SA=41.50\pi\ cm^{2}$

Step-by-step explanation:

Part 1) Find the lateral area of the cone

The lateral area of the cone is equal to

$LA=\pi rl$

we have

$r=1\ cm$

$l=2\ cm$

substitute

$LA=\pi (1)(2)$

$LA=2\pi\ cm^{2}$

Part 2) Find the lateral surface area of the cylinder

The lateral area of the cylinder is equal to

$LA=2\pi rh$

we have

$r=1.5\ cm$

$h=12\ cm$

substitute

$LA=2\pi (1.5)(12)$

$LA=36\pi\ cm^{2}$

Part 3) Find the surface area of the crayon

The surface area of the crayon is equal to the lateral area of the cone, plus the lateral area of the cylinder, plus the top area of the cylinder plus the bottom base of the crayon

Find the area of the bottom base of the crayon

$A=\pi[r2^{2}-r1^{2}]$

where

r2 is the radius of the cylinder

r1 is the radius of the cone

substitute

$A=\pi[1.5^{2}-1^{2}]$

$A=1.25\pi\ cm^{2}$

Find the area of the top base of the cylinder

$A=\pi(1.5)^{2}=2.25\pi\ cm^{2}$

Find the surface area

$SA=2\pi+36\pi+2.25\pi+1.25\pi=41.50\pi\ cm^{2}$

8 0

3 years ago

Read 2 more answers

Lurinda ordered some boxes of greating cards online the cost of the cards is $6.50n + $3 where n is the number of boxes orderd a

Neporo4naja [7]

Answer:

$55

Step-by-step explanation:

For this question you would have to multiply

6.50*8 which equals $52

Then add 3 dollars for the total 52+3=55

6 0

3 years ago