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3 years ago

5

Find -sqrt(36 O t6 O -6 O 6 O 18

1 answer:

gavmur [86]3 years ago

8 0

-sqrt(36) = -6

Hope this helps :)

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Helen has an old laser printer that can print 900 pages in 1.5 hours. If the speed of printing remains constant, how

lilavasa [31]

Answer:

1 hour

Step-by-step explanation:

No. of pages print in 1.5 hours = 900

dividing LHS and RHS by 1.5 so that we get 1 hour in LHS

no. of page print in 1.5/1.5 (1) hours = 900/1.5 = 600.

Thus, it takes 1 hour to print 600 pages.

Given that we have to find how

long will it take her to print a book of 600 pages.

Answer is 1 hour.

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3 years ago

Given the equation of a circle. X^2+ y^2 - 6x + 2y +1 = 0, find the coordinates of the center and the length of the radius.

eimsori [14]

Answer:

I know the answer but you may select me as Brainliest

8 0

2 years ago

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6th grade math help me please !

antiseptic1488 [7]

First we have to figure out how much 3 bags cost using the total cost of $8.25

That means. we would do 8.25/3 and 8.25 divide by 3 equals 2.75.

Now we know that each bag costs approximately $2.75

All we have to do now is multiply 2.75 by 4 to get the cost for the total of 4 bags.

4 times 2.75 is exactly 11 dollars, if might change if theres tax.

But, the answer would be 4 bags costs $11.

6 0

3 years ago

In how many ways can you arrange 9 performers in a row on a stage?

Vinil7 [7]

No of ways = 9! = 362880
The fourth option is correct.

Hope it helped!

8 0

4 years ago

Read 2 more answers

Two distinct number cubes, one red and one blue, are rolled together. Each number cube has sides numbered 1 through 6.

cestrela7 [59]

Answer:

$P(E_1 or E_2) = \frac{7}{12}$

Step-by-step explanation:

Given

Two cubes of side 1 - 6

Required

Probability that the outcome of the roll is an odd sum or a sum that is a multiple of 5

First, the sample space needs to be listed;

Let $C_r$ represent the Red cube

$C_b$ represent the Blue cube

S represent the sample space

$C_r = (1,2,3,4,5,6)\\C_b = (1,2,3,4,5,6)\\S = (2,3,4,5,6,7,3,4,5,6,7,8,4,5,6,7,8,9,5,6,7,8,9,10,6,7,8,9,10,11,7,8,9,10,11,12)$ S is gotten by getting the sum of $C_r$ and $C_b$

$n(S) = 36$

<em>Calculating the Probability</em>

Let $E_1$ represent the event that an outcome is an odd sum

$E_1 = (3,5,7,3,5,7,5,7,9,5,7,9,7,9,11,7,9,11)$

$n(E_1) = 18$

$P(E_1) = \frac{n(E_1)}{n(S)}$

$P(E_1) = \frac{18}{36}$

Let $E_2$ represent the event that an outcome is a multiple of 5

$E_2 = (5,5,5,5,10,10,10)$

$n(E_2) = 7$

$P(E_2) = \frac{n(E_2)}{n(S)}$

$P(E_2) = \frac{7}{36}$

Let $E_3$ represent the event that an outcome is an odd sum and a multiple of 5

$E_3 = E_1 and E_2$

$E_3 = (5,5,5,5)$

$n(E_3) = 4$

$P(E_3) = \frac{n(E_3)}{n(S)}$

$P(E_3) = \frac{4}{36}$

Calculating $P(E_1 or E_2)$

$P(E_1 or E_2) = P(E_1) + P(E_2) - P(E_1 and E_2)$

$P(E_1 or E_2) = P(E_1) + P(E_2) - P(E_3)$

$P(E_1 or E_2) = \frac{18}{36} + \frac{7}{36} - \frac{4}{36}$

$P(E_1 or E_2) = \frac{18 + 7 - 4}{36}$

$P(E_1 or E_2) = \frac{21}{36}$

$P(E_1 or E_2) = \frac{7}{12}$

Hence, the probability that the outcome of the roll is an odd sum or a sum that is a multiple of 5 is $\frac{7}{12}$

6 0

3 years ago