First, create an illustration of the motion of the two cars as shown in the attached picture. The essential equations used is
For constant acceleration:
a = v,final - v,initial /t
The solutions is as follows:
a = v,final - v,initial /t
3.8 = (v - 0)/2.8 s
v = 10.64 m/s After 2.8 seconds, the speed of the blue car is 10.64 m/s.
Answer:
19.21ms-¹
Explanation:
that is the solution above
True because when the independent answer changes, then the dependent variable, which relies on the independent variable, changes.
Answer:
α = -9.67 rad/s²
Explanation:
the magnitude of the angular acceleration of the wheel can be calculated using the expression below;
ω² = ω₀² + 2α(θ- θ₀)..............eqn(1)
ω² = ω₀² + 2αΔθ...............eqn(2)
Δθ= θ- θ₀= 15.6 rad
ω = 13.5 rad/s
ω₀ = 22.0 rad/s
where ω₀= initial angular velocity
ω= final angular velocity
We can now input all the parameters into the equation(2) above
(13.5)² = (22.0)² + 2αΔθ
2αΔθ= (13.5)² - (22.0)²
2αΔθ= 182.25 - 484
2αΔθ=301.75
But our Δθ= 15.6 rad
2α *15.6 rad = 301.75
2α=301.75/15.6
2α=19.343
α=9.67
the magnitude of the angular acceleration of the wheel is 9.67 rad/s²
