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Ostrovityanka [42]
3 years ago
11

Consider a uniformly charged sphere of total charge Q and radius R centered at the origin. We want to find the electric field in

side the sphere (r
Physics
1 answer:
laiz [17]3 years ago
8 0

Answer:

Hello your question is incomplete attached below is the complete question

answer :

Total charge enclosed within the sphere : \frac{q_{r1} }{4\pi e_{0}R^3 } . r

Total charge enclosed outside the sphere : \frac{q}{4\pi e_{0}r^2 } .r

Explanation:

Given data:

Total charge of a uniformly charged sphere = Q

radius = R

first step : find the electric field inside and outside the uniformly charged sphere

2nd step : determine the total charge enclosed within and outside the sphere

make a sketch of the uniformly charged sphere

Attached below is a detailed solution

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A. The acceleration during the slide is 6.86 m/s²

B. The time taken to slide until he stops is 1.2 s

<h3>How to determine the force of friction</h3>
  • Mass (m) = 81.5 Kg
  • Coefficient of friction (μ) = 0.7
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Normal reaction (N) = mg = 81.5 × 9.8 = 798.7 N
  • Frictional force (F) =?

F = μN

F = 0.7 × 798.7

F = 559.09 N

<h3>A. How to determine the acceleration</h3>
  • Mass (m) = 81.5 Kg
  • Frictional force (F) = 559.09 N
  • Acceleration (a) =?

a = F / m

a = 559.09 / 81.5

a = 6.86 m/s²

<h3>B. How to determine the time </h3>
  • Initial velocity (u) = 8.23 m/s
  • Final velocity (v) = 0 m/s
  • Decceleration (a) = -6.86 m/s²
  • Time (t) =?

a = (v – u) / t

t = (v – u) / a

t = (0 – 8.23) / -6.86

t = 1.2 s

Learn more about acceleration:

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4 0
2 years ago
PLEASE ANSWER ASAP!!! ITS DUE IN 10 MINUTES!!!!!!
forsale [732]

Explanation:

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Hope it helps..

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3 years ago
Podocytes are also called<br> 1 poin
gulaghasi [49]
Visceral epithelial cells
5 0
3 years ago
Cho hai điện tích q1=q2=8.10^-7 C đặt cách nhau 5cm. Xác định cường độ điện trường tại điểm:
Aleksandr [31]

Answer: b

Explanation:

5 0
3 years ago
A 150 g sample of brass at 100 °C is placed in a Styrofoam cup of water containing 120 mL of water at 10 °C. No heat is lost to
fredd [130]

Answer:

≈19.144°C.

Explanation:

all the details are in the attachment.

Note, that c₁, m₁, t₁ are the parameters of the sample of brass; c₂, m₂ and t₂ are  the parameters of the sample of water.

P.S. change the provided design according Your requirements.

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2 years ago
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