Answer:
Maximum distance of image from mirror is equal to focal length of the mirror
Explanation:
As we know by the equation of mirror we have

here we know for convex mirror
object position is always negative as it will be placed behind the mirror always
while the focal length of the convex mirror is always taken positive
So here we have


so here maximum value of image distance is equal to focal length of the mirror
Answer:
60Watts
Explanation:
Given parameters:
Current = 0.5A
Voltage = 120V
Unknown
Power = ?
Solution:
The power in the electric circuit is the product of current and voltage;
P = IV
Insert the given parameters and solve;
P = 0.5 x 120
P = 60Watts
If you mean pattern designs it’s rocky bumpy and you can see the circle patterns
If you mean phases the here’s a picture
I have a hunch that you're not talking about overtime
OR overtune. I think you're going for overtone .
For a fundamental frequency of 528 Hz,
1,056 Hz is the second harmonic.