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DENIUS [597]
3 years ago
5

What are the condition required for reverberation?​

Physics
1 answer:
Luda [366]3 years ago
8 0

Answer:

Reverberation is created when a sound produced in a sapce is reflected off surfaces, like walls, teh floor or the ceiling. ... The time it takes for this sound in the space to decrease in volume down to 60 decibels (practically silence) after the sound source is extinguished is its reverberation time.

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Which element has 24 protons
TEA [102]

<u>Answer:</u>

<u>Answer:Chromium</u>

Explanation:

Chromium is the first element in the sixth column of the periodic table. It is classified as a transition metal. Chromium atoms have 24 electrons and 24 protons with the most abundant isotope having 28 neutrons.

4 0
3 years ago
What is fear appeal and how is it used in piblic health
mezya [45]

Quick definition: fear appeal: making someone do something out of fear of something.

I think the way it's used is that doctors make people dear disease.

4 0
3 years ago
What is wireless electricity​
MA_775_DIABLO [31]

Answer:

Transfer of electricity without wire , is known as wireless electricity.

Sir Nicola Tesla came up with this concept.

5 0
3 years ago
What is the sprinters output at 2.0 s, 4.0 s and 6.0 s?
kari74 [83]

A 59 kg sprinter, starting from rest, runs 47 m in 7.0 s at constant acceleration.?  

What is the sprinter's power output at 2.0 s, 4.0 s, and 6.0 s?  

Instantaneous Power is the force times velocity  

P = Fv  

Because the acceleration is constant, the force will be constant as well  

F = ma  

P = mav  

for constant acceleration, the velocity at each time is found using  

v = at  

P = ma(at) = ma²t  

find the acceleration using kinematic equation  

s = ½at²  

a = 2s/t²  

a = 2(47) / 7.0²  

a = 1.918 m/s²  

P(2.0) = 59(1.918²)2.0 = 434.25 W = 0.43 kW  

P(4.0) = 59(1.918²)4.0 = 868.51 W = 0.87 kW  

P(6.0) = 59(1.918²)6.0 = 1302.76 W = 1.3 kW  

I hope this helped.  


5 0
4 years ago
You have been working on a new, strong, lightweight ceramic which will be used to replace steel bearing balls. One cubic meter o
marin [14]

Answer:

r=2.6 cm

Explanation:

Hi!

Lets call steel material 1, and the new alloy material 2. You know their densities:

\rho_1=8.08*10^3\frac{kq}{m^3}\\\rho_2=3.14*10^3\frac{kq}{m^3}

The volume of a sphere with radius r is given by:

V=\frac{4}{3}\pi r^3

Then the masses of the bearings are:

m_1=\rho_1V_1=\frac{4}{3}\pi r_1^3 \\m_1=\rho_2V_2=\frac{4}{3}\pi r_2^3

For the masses to be the same:

\rho_1 V_1 = \rho_2 V_2\\\frac{V_2}{V_1} =\frac{\rho_1}{\rho_2}\\(\frac{r_2}{r_1})^3 = \frac{8.08}{3.14}=2.57\\r_2=\sqrt[3]{2.57}\;r1 =1.37r_1=1.37*1.9cm=2.6cm

5 0
4 years ago
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