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3 years ago

What is the degree of 7x^6 ?

1 answer:

3 0

Example -

4x2 + 6x + 5

This polynomial has three terms. The first one is 4x2, the second is 6x, and the third is 5

The exponent of the first term is 2

The exponent of the second term is 1 because 6x = 6x1

The exponent of the third term is 0 because 5 = 5x0

What? 5x0 = 5?

Well, anything with an exponent of 0 is always equal to 1

So, 5x0 = 5 × x0 = 5 × 1 = 5

Since the highest exponent is 2, the degree of 4x2 + 6x + 5 is 2

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7(x-3)+6=5x-9 please solve the equation fully

TiliK225 [7]

Answer:

I love algebra anyways

The ans is x=3 steps is in the picture with the ans

(hope this helps can i plz have brainlist :D hehe)

Step-by-step explanation:

4 0

3 years ago

Line g passes through points (5, 9) and (3, 2). Line h passes through points (9, 10) and (2, 12). Are line g and line h parallel

icang [17]

For this case we find the slopes of each of the lines:

The g line passes through the following points:

$(x_ {1}, y_ {1}) :( 3,2)\\(x_ {2}, y_ {2}) :( 5,9)$

So, the slope is:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {9-2} {5-3} = \frac {7} {2}$

Line h passes through the following points:

$(x_ {1}, y_ {1}) :( 9,10)\\(x_ {2}, y_ {2}) :( 2,12)$

So, the slope is:

$m = \frac {y_ {2} -y_ {1}}{x_ {2} -x_ {1}} = \frac {12-10} {2-9} = \frac {2} {- 7} = - \frac {2} {7}$

By definition, if two lines are parallel then their slopes are equal. If the lines are perpendicular then the product of their slopes is -1.

It is observed that lines g and h are not parallel. We verify if they are perpendicular:

$\frac {7} {2} * - \frac {2} {7} = \frac {-14} {14} = - 1$

Thus, the lines are perpendicular.

Answer:

The lines are perpendicular.

8 0

3 years ago

URGENT!! GEOMETRY DILATIONS AND TRANSLATIONS!!! BRAINLIEST WILL BE GIVEN !! BOGUS ANSWERS WILL BE BLOCKED !!

nekit [7.7K]

The answer is the same as it was for your other posting of this question at brainly.com/question/10712448

dilation magnitude: 2/3

translation: 5 to the left and 4 down

4 0

3 years ago

the area of a rectangle is 42.15 square meters. if the length is 21 meters, what is perimeters of the rectangle?

Vsevolod [243]

Answer:

perimeters of the rectangle=p=46.014 metres

Step-by-step explanation:

Given that:

Length (l) = 21 m

Area of rectangle(A) = 42.15 meter-square

Width (w)=?

Required data:

Perimater of Rectangle=p=?

Calculation:

As we know that Area of rectangle=A=l*w

Putting the value we get

42.15 m(square)=(21 m)*w

or w=42.15/21

or w=2.007 m

Now to find perimters of rectangle we know that

p=2(l + w) metres

putting the values

p=2(21+2.007) metres

p=2(23.007) metres

p=46.014 metres

7 0

3 years ago

Read 2 more answers

a square has the side measurment of s = 2 3 over 2 using the formula 1= s^2 find the area of the square

vitfil [10]

Check the picture below.

$\bf A=s^2\qquad s=2\frac{3}{2}\qquad A=\left( 2\frac{3}{2} \right)^2\implies A=\left( \frac{2\cdot 2+3}{2} \right)^2
\\\\\\
A=\left( \frac{7}{2} \right)^2\implies A=\cfrac{7^2}{2^2}\implies A=\cfrac{49}{4}\implies A=12\frac{1}{4}$

3 0

3 years ago