P1
Explanation:
The final pressure in the vessel is the same as that of the start of the reaction. We can use the simplification of the combined gas law to solve this problem.
The combined gas law is expressed mathematically as;
P1 is the original pressure
T1 is the initial pressure = 600k
P2 is the final pressure = P2
T2 is the final temperature = 600K
Unknown is the final pressure of the reaction
Input the parameters
This leaves us with P1 = P2
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Answer:
A sample of pure NO2 is heated to 338 ∘C at which temperature it partially dissociates according to the equation 2NO2(g)⇌2NO(g)+O2(g) At equilibrium the density of the gas mixture is 0.515 g/L at 0.745 atm .
(4x^2)x
Kc= -----------
(A-2x)^2
PV=nRT
n/v = P/RT = .745/(0.0821)(334+273) = .01495
To Find the initial molarity of NO2
(mol/L)(g/mol) + (mol/L)(g/mol) + (mol/L)(g/mol)= g/L
Thus:
46(A-2x) + 2x(30) + 32x = .515 g/L
46A-92x+60x+32x = .515
46A=.515
A=.01120 M
Using the total molarity found
(A-2x)+2x+x = .01495 M
A+x=.01495
Plug in A found into the above equation:
.01120+x = .01495
x=.00375
Now Plug A and x into the original Equilibrium Constant Expression:
(4x^2)x
Kc= -----------
(A-2x)^2
Kc = 0.000014
Explanation:
Answer:
i think it is d hope this helps
To calculate your weight in Newton's simply use the following equation to solve for the weight.
Fg = m • g
Fg = 60 kg • 9.81 m/s^2
Fg = 588.6 kgm/s^2
Fg = 588.6 N.
Acceleration due to gravity on earth is 9.81 m/s ^2.
Answer:
0.84kg of gatorade powder
Explanation:
From the question given, we were told that 0.6kg of gatorade powder required 5 gallons of water.
To obtain the mass of gatorade needed for 7 gallons of water, we simply do the following:
0.6kg of gatorade powder required 5 gallons of water.
Therefore, xkg of gatorade powder will require 7 gallons of water i.e
xkg of gatorade powder = (0.6 x 7)/5
xkg of gatorade powder = 0.84kg
Therefore, 0.84kg of gatorade powder will be required.
