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Degger [83]
1 year ago
10

Select all the correct answers.

Chemistry
1 answer:
andrey2020 [161]1 year ago
3 0

The  properties which keep the water temperature from changing much are;

  • water's high specific heat capacity
  • the large mass of water
<h3>What is specific heat capacity?</h3>

The specific heat capacity is the property of a substance that shows how much its temperature changes when it is exposed to heat.

Thus, the  properties which keep the water temperature from changing much are;

  • water's high specific heat capacity
  • the large mass of water

Missing parts:

A red-hot iron nail is immersed in a large bucket of water. Although the nail cools down sufficiently to be held bare-handed, the temperature of the water barely increases. Which properties keep the water temperature from changing much?

A.) water's high heat conductivity

B.) water's high specific heat capacity

C.) the iron nail's high heat conductivity

D.) the large mass of water

E.) the iron nail's high specific heat capacity

Learn more about heat capacity:brainly.com/question/12244241

#SPJ1

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Novay_Z [31]
<span> d. Reduced visibility

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Which type of molecule is shown below?
zubka84 [21]

Answer:

\boxed{\mathrm{Alkene}}

Explanation:

The hydrocarbon shown has a double bond. Hydrocarbons with double bonds are known as alkenes.

Cyclic alkanes have cyclic structure.

Alkanes only have single bonds.

Alkynes have triple bonds.

8 0
3 years ago
Read 2 more answers
A sample of gas X occupies 10 mº at a pressure of 120 kPa.
Mashutka [201]

Answer:

The new pressure of the gas comes out to be 400 KPa.

Explanation:

Initial volume of gas = V = 10\textrm{ m}^{3}

Initial pressure of gas = P = 120 KPa

Final volume of gas = V' = 3\textrm{ m}^{3}

Assuming temperature to be kept constant.

Assuming final pressure of the gas to be P' KPa

PV = P'V' \\120\textrm{ KPa}\times 10\textrm{ m}^{3} = \textrm{P'}\times 3\textrm{ m}^{3} \\\textrm{P'} = 400\textrm{ KPa}

New pressure of gas = 400 KPa

5 0
2 years ago
If 5. 0 grams of kcl is dissolved in 500 ml of water, what is the concentration of the resulting solution?
Lady_Fox [76]

If 5.0 grams of KCl is dissolved in 500 ml of water, the concentration of the resulting solution will be 0.134M.

<h3>How to calculate concentration?</h3>

The concentration of a solution can be calculated by using the following formula;

Molarity = no of moles ÷ volume

According to this question, 5.0 grams of KCl is dissolved in 500 ml of water. The concentration is calculated as follows:

no of moles of KCl = 5g ÷ 74.5g/mol = 0.067mol

Molarity = 0.067mol ÷ 0.5L = 0.134M

Therefore, if 5.0 grams of KCl is dissolved in 500 ml of water, the concentration of the resulting solution will be 0.134M.

Learn more about concentration at: brainly.com/question/10725862

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6 0
1 year ago
An inflated balloon is left outside overnight. initially it has a volume of 1.84 L when the temperature is 293.4 K and the press
Mrac [35]

Answer:

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Explanation:

5 0
3 years ago
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