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riadik2000 [5.3K]
2 years ago
6

Measurements show that unknown x compound has the following composition:

Chemistry
1 answer:
Fudgin [204]2 years ago
7 0

The empirical formula of the compound with the percent composition C 18.1%, H 2.27%, Cl 79.8% is C₂H₃Cl₃.

<h3>What is an empirical formula?</h3>

It is the minimum ratio between the elements that form a compound.

  • Step 1: Divide each percentage by the molar mass of the element.

C: 18.1/12.01 = 1.51

H: 2.27/1.01 = 2.25

Cl: 79.8/35.45 = 2.25

  • Step 2: Divide all the numbers by the smallest one.

C; 1.51/1.51 = 1

H: 2.25/1.51 ≈ 1.5

Cl: 2.25/1.51 ≈ 1.5

  • Step 3: Multiply all the numbers by 2 so all of them are whole.

C: 1 × 2 = 2

H: 1.5 × 2 = 3

Cl: 1.5 × 2 = 3

The empirical formula is C₂H₃Cl₃.

The empirical formula of the compound with the percent composition C 18.1%, H 2.27%, Cl 79.8% is C₂H₃Cl₃.

Learn more about empirical formula here: brainly.com/question/1603500

#SPJ1

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The air in a bicycle tire is bubbled through water and collected at 25 ∘C. If the total volume of gas collected is 5.30 L at a t
Klio2033 [76]

<u>Answer:</u> The number of moles of gas in bicycle tire is 0.210 moles

<u>Explanation:</u>

To calculate the moles of gas, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 737 torr

V = Volume of the gas = 5.30 L

T = Temperature of the gas = 25^oC=[25+273]K=298K

R = Gas constant = 62.364\text{ L. Torr }mol^{-1}K^{-1}

n = number of moles of gas = ?

Putting values in above equation, we get:

737Torr\times 5.30L=n\times 62.364\text{ L Torr }mol^{-1}K^{-1}\times 298K\\\\n=\frac{737\times 5.30}{62.364\times 298}=0.210mol

Hence, the number of moles of gas in bicycle tire is 0.210 moles

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4 years ago
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iren2701 [21]
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A brick measures 0.018 dam by 6.5 cm by 17.3 cm. What is the volume of the brick in cubic centimeters
erastova [34]

Answer:

volume of brick= length × breadth × height

=0.000018 ×6.5×17.3

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What is the wavelength of light emitted between the 3 rd and 1 st energy levels? 121.5 nm 94.5 nm 102.5 nm 1875 nm
Sauron [17]
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The compound dioxane, which is used as a solvent in various industrial processes is composed of C,H, and O atoms. Combustion of
Lady_Fox [76]

Answer:

The correct formula of dioxane is C₄H₈O₂.

Explanation:

Given data:

mass of dioxane= 2.23 g

mass of water = 1.802 g

mass of carbon dioxide = 4.401 g

molar mass of dioxane = 88.1 g / mol

Molecular formula of dioxane = ?

Solution:

percentage of carbon = (4.401 g/2.23 g ) × (12 /44) × 100

                                     =  (1.98 × 0.273) × 100 = 54.1

percentage of hydrogen =  (1.802 g/ 2.23 g) × (2.016 /18.016) × 100

                                         = (0.81 × 0.112) × 100 = 9.072

percentage of oxygen = 100 - (54.1 + 9.072)

                                     = 100 - 63.172 = 36.828

Now we will determine the number of grams atoms of carbon, hydrogen and oxygen.

No. of gram atoms of carbon = 54.1 /12 = 4.51

No. of gram atoms of hydrogen = 9.072 / 1.008 = 9

No. of gram atoms of oxygen = 36.828 / 16 = 2.302

Atomic ratio:

    C :H :O               4.51/ 2.302    :   9 / 2.302   :  2.302 /2.302

    C :H :O                2 : 4 : 1

Molecular formula:

   Molecular formula = n × (empirical formula)

   n = molar mass of compound / empirical formula mass

   empirical formula mass= 2 × 12 + 4 × 1.008  + 1 × 16

    empirical formula mass= 24+ 4.032 +16 = 44.032

                 n = 88.1 / 44.032 = 2

        Molecular formula = n × (empirical formula)

        Molecular formula = 2 × (C₂H₄O)

         Molecular formula = C₄H₈O₂

8 0
3 years ago
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