Answer:
Well ads I remember, the motion of the gas particles is random and in a straight-line. A sample of gas is contained in a closed rigid cylinder.
And here is what I found too -
According to Kinetic Molecular Theory, gaseous particles are in a state of constant random motion; individual particles move at different speeds, constantly colliding and changing directions. We use velocity to describe the movement of gas particles, thereby taking into account both speed and direction.
Answer:
analogue and digital media is a nightmare to be able
Enthalpy change during the dissolution process = m c ΔT,
here, m = total mass = 475 + 125 = 600 g
c = <span>specific heat of water = 4.18 J/g °C
</span>ΔT = 7.8 - 24 = -16.2 oc (negative sign indicates that temp. has decreases)
<span>
Therefore, </span>Enthalpy change during the dissolution = 600 x 4.18 X (-16.2)
= -40630 kJ
(Negative sign indicates that process is endothermic in nature i.e. heat is taken by the system)
Thus, <span>enthalpy of dissolving of the ammonium nitrate is -40630 J/g</span>
Hey there!
There are 6.022 x 10²³ atoms in one mole.
We have 5.33 x 10⁻⁵ moles.
(5.33 x 10⁻⁵) x (6.022 x 10²³)
3.21 x 10¹⁹
There are 3.21 x 10¹⁹ atoms in 5.33 x 10⁻⁵ mol C.
Hope this helps!
Answer:
The final pressure is 0.788 atm (option b).
Explanation:
Boyle's law says that the volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure. That is: if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases. This is expressed mathematically as the product of pressure times volume equal to a constant value:
P*V=k
Assuming a certain volume of gas V1 that is at a pressure P1 at the beginning of the experiment, by varying the volume of gas to a new value V2, then the pressure will change to P2, and it will be fulfilled:
P1*V1=P2*V2
In this case:
- P1= 2.14 atm
- V1= 3 L
- P2= ?
- V2= 8.15 L
Replacing:
2.14 atm*3 L= P2* 8.15 L
Solving:
0.788 atm= P2
<u><em>The final pressure is 0.788 atm (option b).</em></u>
