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vlada-n [284]
3 years ago
13

Phosphorus-32 is radioactive and has a half life of 14.3 days. What percentage of a sample would be left after 12.6 days

Chemistry
1 answer:
nadya68 [22]3 years ago
8 0

Answer:

There is 54.29 % sample left after 12.6 days

Explanation:

Step 1: Data given

Half life time = 14.3 days

Time left = 12.6 days

Suppose the original amount is 100.00 grams

Step 2: Calculate the percentage left

X = 100 / 2^n

⇒ with X = The amount of sample after 12.6 days

⇒ with n = (time passed / half-life time) = (12.6/14.3)

X = 100 / 2^(12.6/14.3)

X = 54.29

There is 54.29 % sample left after 12.6 days

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How many liters of softened water, containing a sodium concentration of 5.2×10−2 % sodium by mass, have to be consumed to exceed
german

Answer:

4423.08 L

Explanation:

First we need to know the concentration of sodium per litre (as the density is 1 g/L, 1 g of water is the same that 1 mL of water) of softened water by dividing the percentage in 100:

5.2x10^{-4}g/L

With the value of concentration, we just need to to divide the recommended value of the FDA, that is 2300 milligrams per day, into the concentration that we have, therefore:

2300mg=2.3g\\\\\frac{2.3g}{5.2x10^{-4}g/L} =4423.08 L

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How much heat must be removed from 357 g of water at 76.9C in order to cool it down to 18.1C?
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How much energy is required when a 142.1 gram sample of aluminum goes from 25.5°C to 46°C? (the specific heat of aluminum is 0.9
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Answer:

2621.75 j heat is required to increase the temperature 25.5°C to 46°C.

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Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

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ΔT = 46°C - 25.5°C

ΔT = 20.5°C

Q = 142.1 × 0.90 J/g.°C × 20.5°C

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