Which elements have electron configurations that end in ns2np5?

Chemistry

2 answers:

Dahasolnce [82]3 years ago

5 0

Explanation:

The given configuration is $ns^{2}np^{5}$ and this shows that there are seven valence electrons present in the outermost shell. Therefore, it is a general configuration of group 17 which is also known as halogen group.

Elements of group 17 are fluorine, chlorine, bromine, iodine and astatine.

For example, fluorine is a group 17 element that has electronic configuration $1s^{2}2s^{2}2p^{5}$ .

Value of n will start from 2 and increases on moving down the group.

Hence, we can conclude that halogens are the elements that have electron configurations that end in $ns^{2}np^{5}$ .

Arada [10]3 years ago

4 0

Last level of atoms of these elements has 2+5= 7 electrons. These elements are located in the 17th group of the Periodic Table, and they are called halogens.

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The following reaction produces ethanoic acid (CHACOOH) from methanol (CH3OH) and carbon

tigry1 [53]

Answer:

$\boxed{\text{300 g}}$

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

M_r: 32 60

CH₃OH + CO ⟶ CH₃COOH

m/g: 160

(a) Moles of CH₃OH

$\text{Moles of CH$_{3}$OH} = \text{160 g CH$_{3}$OH }\times \dfrac{\text{1 mol CH$_{3}$OH }}{\text{32 g CH$_{3}$OH}}= \text{5.00 mol CH$_{3}$OH}$

(b) Moles of CH₃COOH

$\text{Moles of CH$_{3}$COOH} = \text{5.00 mol CH$_{3}$OH } \times \dfrac{\text{1 mol CH$_{3}$COOH}}{\text{1 mol CH$_{3}$OH }} = \text{5.00 mol CH$_{3}$COOH}$

(c) Mass of CH₃COOH

$\text{Mass of CH$_{3}$COOH} =\text{5.00 mol CH$_{3}$COOH} \times \dfrac{\text{60 g CH$_{3}$COOH}}{\text{1 mol CH$_{3}$COOH}} = \textbf{300 g CH$_{3}$COOH}\\\\\text{The maximum mass of ethanoic acid that can be produced is $\boxed{\textbf{300 g}}$}$