Proprietățile fizice ale mineralelor depind in cea mai mare măsură de compozitie chimică si structura reticulara reprezintă importanta deosebită în recunoașterea mineralelor
Answer:
Maybe I know too much chemistry but how the metals (and the non-metals) react depends on where they are in the Periodic Table. The metals in groups I and II over on the far left side are explosively reactive and loose electrons and form ionic bonds. Examples: Na+1 has lost 1 electron and Li+2 has lost 2 electrons. The metals in the higher groups are more confusing but most of them share outer shell electrons and form covalent bonds. Examples: Fe2O3 (rust) where Iron shares 2X3 electrons with Oxygen which shares 3X2 electrons. Confused enough? :-)
The answer you'll be expected to give depends on the subject of the chapter you're studying. If you're studying covalent bonds, then the answer will probably be "form covalent bonds". If you're studying ionic bonds, then the answer will be "lose electrons".
Explanation:
This may not be the answer... I'm sorry if it's not
CaCO₃ is a compound in and of itself thus it is not a polyatomic ion.
<h3>
Answer:</h3>
0.3093 g of glucose are consumed each minute by the body.
<h3>
Explanation:</h3>
- During cellular respiration glucose is broken down in presence of oxygen to yield energy, water and carbon dioxide.
- The equation for the reaction taking place during cellular respiration is;
C₆H₁₂O₆ + 6O₂ → 6H₂O + 6CO₂
We are required to calculate the amount of glucose in grams;
<h3>Step 1: Calculate the moles of glucose broken down</h3>
From the equation, the mole ratio of glucose to Oxygen is 1 : 6
Moles of Oxygen in a minute is 1.03 × 10^-2 moles
Therefore, moles of glucose will be;
= (1.03 × 10^-2)÷6
= 1.717 × 10^-3 moles
<h3>Step 2: Mass of glucose </h3>
Mass is given by multiplying the number of moles with molar mass
mass = moles × molar mass
Molar mass glucose is 180.156 g/mol
Therefore;
Mass = 1.717 × 10^-3 × 180.156 g/mol
= 0.3093 g
Hence, 0.3093 g of glucose are consumed each minute by the body.