Answer:
9717.246 J
Explanation:
From the question given above, the following data were obtained:
Mass (m) of water = 40.5 g
Initial temperature (T₁) = 15.6 °C
Final temperature (T₂) = 73 °C
Specific heat capacity (C) of water = 4.18 J/gºC
Heat (Q) =.?
Next, we shall determine the change in the temperature of water. This can be obtained as follow:
Initial temperature (T₁) = 15.6 °C
Final temperature (T₂) = 73 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 73 – 15.6
ΔT = 57.4 °C
Finally, we shall determine the heat energy required. This can be obtained as follow:
Mass (m) of water = 40.5 g
Specific heat capacity (C) of water = 4.18 J/gºC
Change in temperature (ΔT) = 57.4 °C
Heat (Q) =.?
Q = MCΔT
Q = 40.5 × 4.18 × 57.4
Q = 9717.246 J
Thus, the heat energy required is 9717.246 J
