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Anna71 [15]
3 years ago
15

The table shown below shows some values for functions f(x) and g(x). What is/are the solution(s) to f(x)=g(x)? Explain your answ

er(s).

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
5 0

Answer: x = -1 and x = 1

Step-by-step explanation:

The solution to f(x) = g(x) is the point at which the two intersect , that is , the point at which they are equal. Checking through the table given ,it is only 9 and 12 that is common to both f(x) and g(x) .

Therefore : the solution to f(x) = g(x) is the point where x = -1 and x = 1

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Marry Emma earned $45.00 babysitting her cousin. She saved $18.50 and spent the remainder. How much did Mary Emma spend?
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Answer:

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2 years ago
The function f(x) varies directly with x, and f(x) = 45 when x = 9.
Paladinen [302]

Answer:

Option C = 15

Step-by-step explanation:

In principle when a function <em>f(x) </em>varies directly with <em>x</em> it suggests that any changes in x results in the equivalent changes in<em> f(x)</em>. If we have two variables, i.e. <em>y</em> representing<em> f(x)</em> and <em>x</em> representing itself, any increment/decrement in <em>x</em> will result to the same increment/decrement in <em>y</em> by a factor <em>a, thus we can say that y = ax, implying y and x have the same ratio. </em>

In the given question we know that <em>f(x) = 45</em> when x=9<em>, </em>which translates as

f(x=9) = 45

This tells us that f(x) varies by a factor (lets call it) a for a given value of x.

To find this factor we can just divide 45 with 9 which gives: \frac{45}{9} = 5

Thus the factor a here is a=5 which finally tells us that

f(x) = 5x    Eqn (1) our original function.

Since we now know our function we can plug in the value for x=3 and solve for f(x=3) as follow:

f(x=3)= 5*3

f(x=3) = 15

f(3) = 15

Looking at the given options in the question we can conclude that the correct answer is Option C = 15

3 0
3 years ago
Simplify this please.
Natali5045456 [20]

Answer:

tbh i just used another app to help me help you i hope this is right the app i used is always spot on with answers :)

4 0
3 years ago
Read 2 more answers
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