Let n be an integer. What is the product of five times the integer added to to times the next consecutive integer?

Mathematics

1 answer:

Zanzabum3 years ago

4 0

Let n be the first integer and n + 1 the next consecutive integer
5n + (n + 1)
6n + 1

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HELP POINTS A LOt! BRAINLIEST!

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2 years ago

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Solve xy - 3 = k solve for x

ladessa [460]

Answer:

x=(k+3)/y

Step-by-step explanation

First, we simplify by adding 3 to both sides of the equation

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A device produces random 64-bit integers at a rate of one billion per second. After how many years of running is it unavoidable

nikitadnepr [17]

Answer:

3171 × 10^(44) years

Step-by-step explanation:

For each bit, since we are looking how many years of running it is unavoidable that the device produces an output for the second time, the possible integers are from 0 to 9. This is 10 possible integers for each bit.

Thus, total number of possible 64 bit integers = 10^(64) integers

Now, we are told that the device produces random integers at a rate of one billion per second (10^(9) billion per second)

Let's calculate how many it can produce in a year.

1 year = 365 × 24 × 60 × 60 seconds = 31,536,000 seconds

Thus, per year it will produce;

(10^(9) billion per second) × 31,536,000 seconds = 3.1536 × 10^(16)

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Number of years of running is it unavoidable that the device produces an output for the second time is;

(10^(64))/(3.1536 × 10^(16)) = 3171 × 10^(44) years

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3 years ago

Which expressions are equivalent to 7x – 14? Check all that apply. 14 – 7x x – 2 –(14 – 7x) 7(x – 2) 3x – 14 4x 2x – 10 5x 4.

kondaur [170]

Linear equation are the equation which has the highest power of the unknown variable is 1.The expressions given in the option 1, 2, and 3 are equivalent to $7x - 14$ .