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lianna [129]
3 years ago
12

PLEASE HELP!

Chemistry
2 answers:
leva [86]3 years ago
6 0
A is the correct answer.
lukranit [14]3 years ago
4 0
The answer to your question is A
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Write the balanced equation. Then calculate the volume of 0.65 M HCl required to completely neutralize 400.0 ml of 0.88 M KOH.
Misha Larkins [42]
Hello!

The balanced equation for the neutralization of KOH is the following:

HCl(aq) + KOH(aq) → KCl(aq) + H₂O(l)

To calculate the volume of HCl required, we can apply the following equation:

 moles HCl = moles KOH \\  \\ cHCl*vHCl=cKOH*vKOH \\  \\ vHCl= \frac{cKOH*vKOH}{cHCl}= \frac{400 mL*0,88M}{0,65M}=  541,54mL

So, the required volume of HCl is 541,54 mL

Have a nice day!
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To answer the question we need to know the following;

What are valence electrons?

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What is the reactivity of halogens?

  • Halogens are the most reactive non-metals in the periodic table. They react by gaining one electron to attain a stable configuration.
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