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Advocard [28]
3 years ago
11

Write a balanced chemical equation for the photosynthesis reaction in which gaseous carbon dioxide and liquid water react in the

presence of chlorophyll to produce aqueous glucose (c6h12o6) and oxygen gas.
Chemistry
2 answers:
allochka39001 [22]3 years ago
8 0

Answer:

6CO_2(aq)+6H_2O(l) \rightarrow C_6H_{12}O_6(aq)+6O_2(g)

Explanation:

Photosynthesis is a process by which plants and other autotrophic organisms make their own food.

In the process of photosynthesis, chlorophyll traps the light energy of the sun and this energy is used for the synthesis of glucose from carbon dioxide and water. In this process oxygen is released as byproduct.

The balanced chemical equation for photosynthesis is:

6CO_2(aq)+6H_2O(l) \rightarrow C_6H_{12}O_6(aq)+6O_2(g)

So, in the process of photosynthesis, light energy is converted to chemical energy in the form of glucose.

antoniya [11.8K]3 years ago
6 0
6CO2 + 6H2O = C6H12O6 + 6O2

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The Ka of an acid is 1.3 x 10–7. Based on the Ka and its relationship with Kw, what is the value of Kb?
Solnce55 [7]
Ka x Kb = Kw      Kw = 1 x 10⁻¹⁴

(1.3 x 10⁻⁷) x Kb = 1 x 10⁻¹⁴

Kb = ( 1 x 10⁻¹⁴ ) / ( 1.3 x 10⁻⁷)

Kb = 7.7 x 10⁻⁸

Answer D

hope this helps!

6 0
3 years ago
Read 2 more answers
if 3.0 grams of aluminum and 6.0 grams of bromine react to form AlBr3, how many grams of product would theoretically be produced
Gelneren [198K]
1) Chemical reaction: 2Al + 3Br₂ → 2AlBr₃.
m(Al) = 3,0 g.
m(Br₂) = 6,0 g.
n(Al) = m(Al) ÷ M(Al).
n(Al) = 3,0 g ÷ 27 g/mol.
n(Al) = 0,11 mol.
n(Br₂) = n(Br₂) ÷ m(Br₂).
n(Br₂) = 6 g ÷ 160 g/mol.
n(Br₂) = 0,0375 mol; limiting reagens.
n(Br₂) : n(AlBr₃) = 3 : 2.
n(AlBr₃) = 0,025 mol.
m(AlBr₃) = 0,025 mol · 266,7 g/mol.
m(AlBr₃) = 6,67 g.

2) m(Br₂) - all bromine reacts, so mass of bromine after reaction is zero grams (m(Br₂) = 0 g).
n(Al) = 0,11 mol - 0,025 mol = 0,085 mol.
m(Al) = 0,085 mol · 27 g/mol.
m(Al) = 2,295 g.
m(AlBr₃) = 6,67 g · 0,72 (yield of reaction).
m(AlBr₃) = 4,8 g.
n - amount of substance.
M - molar mass.

4 0
3 years ago
how do i caculate the trmperature change that 725 grams of aluminum will undergo when 2.35x10^4 Joules of thermal energy are add
sesenic [268]

Answer:

36°C

Explanation:

Given parameters:

Mass of aluminum = 725g

Quantity of heat  = 2.35 x 10⁴J

Unknown:

Temperature change  = ?

Solution:

To solve this problem, we simply use the expression below:

  The quantity of energy is given as:

          Q  = m C Δt

Q is the quantity of energy

m is the mass

C is the specific heat capacity of aluminum  = 0.9J/g°C

Δt is the change in temperature

  The unknown is Δt;

             Δt  = \frac{Q}{mc}    = \frac{2.35 x 10^{4} }{725 x 0.9}    = 36°C

4 0
3 years ago
The atomic mass of an element most nearly reflects the elements total number of
klemol [59]

Answer:

it's a

Explanation:

<h3> the atomic mass is the number of protons and neutrons in an element added together</h3>

3 0
4 years ago
Read 2 more answers
If there were only three electron groups around an atom, how would they be arranged?
Blizzard [7]
<span>There would be two electrons in the 1s orbital one oriented up and one oriented down. The other electron would be in the 1p orbital up or down. Remember that 1s can only hold 2 electrons at a time, and when it is filled there one electron is spinning up and the other is spinning down. After 1s, comes the 1p orbital which can hold 6 electrons. Until 3 electrons are spinning either up or down, the next one will have the next orientation.</span>
8 0
4 years ago
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