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V125BC [204]
3 years ago
13

Cesium metal is frequently used in photoelectric cells because the amount of energy necessary to eject electrons from a cesium s

urface is relatively small-only 206.5 kJ/mol. Part A What wavelength of light (in nanometers) does this correspond to?

Chemistry
1 answer:
dybincka [34]3 years ago
8 0

Answer:

Wavelength of light in (nm) = 579 nm

Explanation:

At first you find out the amount of energy needed to just eject one electron. This is given by \frac{Energy}{Avogadro's number}

this energy is given in question in kj/mole. This \frac{Energy}{Avogadro's number} is the work function of cesium for each electron is equal to the planc'k  einstein equation.

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Moles of N2O5 = moles of NO2 * ( 2 moles of N2O5 / 4 moles of NO2
3 0
3 years ago
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dsp73

Answer:

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3 years ago
Give 7 and example of how each wave in the EM spectrum in used in our daily lives
bogdanovich [222]
1. it’s use for our food in like microwaves and ovens
2. airplanes are guided by radar waves,
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8 0
3 years ago
How many moles in 4.3 x 1024 atoms of sodium (Na)?
wel

Answer:How many ions are in 2 moles of NaCl?

2 mol NaCl = 2 x 6.02 x 10 23 = 1.204 x 10 24 NaCl formula units 2 mol NaCl = 2 (2 x 6.02 x 10 23 )= 2 (1.204 x 10 24) = 2.408 x 10 24 atoms *2 moles of sodium chloride contains 2.408 x 10 24 ions (combination of Na + ions & Cl – ions). H

Explanation:

sorry i was running out of time

3 0
3 years ago
What volume (in mL) of a 0.200 MHNO3 solution is required to completely react with 27.6 mL of a 0.100 MNa2CO3 solution according
ladessa [460]

Answer:

There is 27.6 mL of a 0.200 M HNO3 solution required

Explanation:

<u>Step 1: </u>The balanced equation is:

Na2CO3(aq)+2HNO3(aq)→2NaNO3(aq)+CO2(g)+H2O(l)

This means for 1 mole Na2CO3 consumed, there is consumed 2 mole of HNO3 and there is produced 2 moles of NaNO3, 1 mole of CO2 and 1 mole of H2O

<u>Step 2: </u>Calculating moles of Na2CO3

moles of Na2CO3 =volume of Na2CO3 * Molarity of Na2CO3

moles of Na2CO3 = 27.6 *10^-3 * 0.1 M = 0.00276 moles

<u>Step 3: </u>Calculating moles of HNO3

In the balanced equation, we can see that for 1 mole of Na2CO3 consumed, there are consumed 2 moles of HNO3.

So for 0.00276 moles consumed of Na2CO3, there are consumed 0.00552 moles of HNO3.

This means 0.00276 moles of the base Na2CO3 would react with 0.00552 moles of the acid HNO3

<u>Step 4: </u>Calculating the volume of HNO3

volume of HNO3 = moles of HNO3 / Molarity of HNO3

volume of HNO3 = 0.00552 moles / 0.200 M  = 0.0276 L

0.0276 L = 27.6 ml

There is 27.6 mL of a 0.200 M HNO3 solution required

4 0
3 years ago
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