The original concentration is 5.1 × 10⁹ CFU / ml
In order to attain a countable plate, the number of CFU must be present in between 10 and 200 per ml.
Let us take 0.1 ml and dilute it to 1 ml.
This minimizes the concentration to 5.1 × 10⁹ × 10⁻¹ = 5.1 × 10⁸ CFU/ml
In order to minimize the concentration in between 10 and 200, it can be reduced to 5.1 × 10¹
The final concentration = 5.1 × 10¹ CFU/ml
Initial concentration = 5.1 × 10⁹ CFU/ml
Volume of sample with 5.1 × 10¹ CFU = 5.1 × 10¹ CFU × (1 ml / 5.1 × 10⁹ CFU)
= 1.0 × 10⁻⁸ ml
This is the volume to be taken to obtain countable value, 51 CFU.
Answer:
vdsfdvdsfdsf
Explanation:
https://newsengin.zendesk.com/hc/vew/community/posts/360056216292-%D9%85%D9%88%D9%82%D8%B9-%D8%A7%D9%84%D9%86%D9%88%D8%B1-%D9%85%D8%B3%D9%84%D8%B3%D9%84-%D8%A7%D9%84%D9%85%D8%A4%D8%B3%D8%B3-%D8%B9%D8%AB%D9%85%D8%A7%D9%86-%D8%A7%D9%84%D8%AD%D9%84%D9%82%D8%A9-8-%D8%A7%D9%84%D8%AB%D8%A7%D9%85%D9%86%D8%A9-%D9%83%D8%A7%D9%85%D9%84%D8%A9-%D9%85%D8%AA%D8%B1%D8%AC%D9%85%D8%A9-%D9%82%D9%8A%D8%A7%D9%85%D8%A9-%D8%B9%D8%AB%D9%85%D8%A7%D9%86-%D8%A7%D9%84%D8%AD%D9%84%D9%82%D8%A9-8-%D9%83%D8%A7%D9%85%D9%84%D8%A9-%D9%85%D8%AA%D8%B1%D8%AC%D9%85%D8%A9
https://newsengin.zendesk.com/hc/pst/community/posts/360056216252-Serial-TV-%D9%85%D8%B3%D9%84%D8%B3%D9%84-%D8%A7%D9%84%D9%85%D8%A4%D8%B3%D8%B3-%D8%B9%D8%AB%D9%85%D8%A7%D9%86-%D8%A7%D9%84%D8%AD%D9%84%D9%82%D8%A9-7-%D8%A7%D9%84%D8%B3%D8%A7%D8%A8%D8%B9%D8%A9-%D8%A7%D9%88%D9%86%D9%84%D8%A7%D9%8A%D9%86-%D8%A7%D9%84%D9%85%D8%A4%D8%B3%D8%B3-%D8%B9%D8%AB%D9%85%D8%A7%D9%86-%D8%A7%D9%84%D8%AD%D9%84%D9%82%D8%A9-7-%D9%83%D8%A7%D9%85%D9%84%D8%A9-%D9%85%D8%AA%D8%B1%D8%AC%D9%85%D8%A9-HD
https://newsengin.zendesk.com/hc/vew/community/posts/360056216292-%D9%85%D9%88%D9%82%D8%B9-%D8%A7%D9%84%D9%86%D9%88%D8%B1-%D9%85%D8%B3%D9%84%D8%B3%D9%84-%D8%A7%D9%84%D9%85%D8%A4%D8%B3%D8%B3-%D8%B9%D8%AB%D9%85%D8%A7%D9%86-%D8%A7%D9%84%D8%AD%D9%84%D9%82%D8%A9-8-%D8%A7%D9%84%D8%AB%D8%A7%D9%85%D9%86%D8%A9-%D9%83%D8%A7%D9%85%D9%84%D8%A9-%D9%85%D8%AA%D8%B1%D8%AC%D9%85%D8%A9-%D9%82%D9%8A%D8%A7%D9%85%D8%A9-%D8%B9%D8%AB%D9%85%D8%A7%D9%86-%D8%A7%D9%84%D8%AD%D9%84%D9%82%D8%A9-8-%D9%83%D8%A7%D9%85%D9%84%D8%A9-%D9%85%D8%AA%D8%B1%D8%AC%D9%85%D8%A9
Answer:
1.008moles of iodine
Explanation:
Hello,
This question requires us to calculate the theoretical yield of I₂ or number of moles that reacted.
Percent yield = (actual yield / estimated yield) × 100
Actual yield = 1.2moles
Estimated yield = ?
Percentage yield = 84%
84 / 100 = 1.2 / x
Cross multiply and solve for x
100x = 84 × 1.2
100x = 100.8
x = 100.8/100
x = 1.008moles
1.008 moles of I₂ reacted in excess of H₂ to give 1.2 moles of HI
<span>58.6934 +/- 0.0002 u</span>
