Answer:
Class interval 10-19 20-29 30-39 40-49 50-59
cumulative frequency 10 24 41 48 50
cumulative relative frequency 0.2 0.48 0.82 0.96 1
Step-by-step explanation:
1.
We are given the frequency of each class interval and we have to find the respective cumulative frequency and cumulative relative frequency.
Cumulative frequency
10
10+14=24
14+17=41
41+7=48
48+2=50
sum of frequencies is 50 so the relative frequency is f/50.
Relative frequency
10/50=0.2
14/50=0.28
17/50=0.34
7/50=0.14
2/50=0.04
Cumulative relative frequency
0.2
0.2+0.28=0.48
0.48+0.34=0.82
0.82+0.14=0.96
0.96+0.04=1
The cumulative relative frequency is calculated using relative frequency.
Relative frequency is calculated by dividing the respective frequency to the sum of frequency.
The cumulative frequency is calculated by adding the frequency of respective class to the sum of frequencies of previous classes.
The cumulative relative frequency is calculated by adding the relative frequency of respective class to the sum of relative frequencies of previous classes.
Answer:
Reflection
Step-by-step explanation:
Here, we want to get the transformation that yielded figure B from figure A
Looking at the plot, we can see that we have the origin as the center of transformation
The kind of transformation however is reflection
The shape A was reflected about the origin or the point (0,0) to give shape B
Answer:
b. 4x-8
Step-by-step explanation:
1/2 x(8x-16)
= 1/2(8x) - 1/2 (16)
=4x - 8
Hope this helped
We use the formula a^2 - b^2 = ( a - b )( a + b );
We have a = 5m - 2 and b = 3m - 4;
<span>(5m-2)^2-(3m-4)^2 = (5m - 2 -3m + 4) x (5m-2 + 3m - 4) = (2m + 2)(8m - 6) = 2(m +1) x 2(4m - 3) = 4(m+1)(4m-3);
</span>
Answer:
There is evidence for the claim that less than 10% of the test results are wrong
Step-by-step explanation:
Given that the company Drug Test Success provides a "1-Panel-THC" test for marihuana usage.
Among 300 tested subjects, results from 27 subjects were wrong (either a false positive or a false negative.)
Sample proportion = 
H0: p = 0.10
Ha: p <0.10
(left tailed test)
p difference = 0.09-0.10 = -0.01
Std error = 
z statistic = -1.9245
p value = 0.027
Since p <0.05 we reject H0
There is evidence for the claim that less than 10% of the test results are wrong
