All categories

2 years ago

What is the magnitude of the resultant of a 7.0-N force acting vertically upward and a 5.0-N force acting horizontally.

Physics

1 answer:

irakobra [83]2 years ago

6 0

Answer:

Resultant force = 8.6N

Explanation:

Using Pythogorus' theorem

${a}^{2} + {b}^{2} = {c }^{2} \\ {7}^{2} + {5}^{2} = {r}^{2} \\ 49 + 25 = {r}^{2} \\ 74 = {r}^{2} \\ \sqrt{74} = \sqrt{ {r }^{2} } \\ 8.6 = r \\$

Resultant force = 8.6N

You might be interested in

A man climbs on to a wall that is 3.6m high and gains 2268J of potential energy. What is the mass of the man? *

Ilia_Sergeevich [38]

The mass of the man is 63 kilograms
There is it written down properly. Its hard to type this stuff in here

3 0

3 years ago

Rahul has 2 bulbs connected across two cells in a simple circuits shown. How can he make the bulbs glow dimmer?

Ray Of Light [21]

Answer:

in the parallel connection the light bulbs shine less than in the series connection

Explanation:

In a series circuit the current through the whole circuit is the same, therefore the power (brightness) of each bulb is

P = i² R

where R is the resistance of each bulb and i the current of the circuit.

If we connect the light bulbs and the cells in parallel, the current in the circuit is the sum of the east that passes through each light bulb,

i = i₁ + i₂

if the two light bulbs are the same

i = 2 i₁

i₁ = i / 2

so the power of each bulb is is

P = i₁² R

P = R i² / 4

P = ¼ P_initial

Therefore we see that in the parallel connection the light bulbs shine less than in the series connection

3 0

2 years ago

I need help with some graph.<br><br> Which graph shows acceleration?

matrenka [14]

Answer:

The first graph

Explanation:

Graph A shows acceleration.

4 0

2 years ago

Read 2 more answers

A truck covers 47.0 m in 8.60 s while smoothly slowing down to final speed of 2.30 m/s. (a) Find its original speed.

Kruka [31]

Explanation:

Given that,

Distance, s = 47 m

Time taken, t = 8.6 s

Final speed of the truck, v = 2.3 m/s

Let u is the initial speed of the truck and a is its acceleration such that :

$a=\dfrac{v-u}{t}$ .............(1)

Now, the second equation of motion is :

$s=ut+\dfrac{1}{2}at^2$

Put the value of a in above equation as :

$s=ut+\dfrac{1}{2}\times \dfrac{v-u}{t}\times t^2$

$s=\dfrac{t(u+v)}{2}$

$u=\dfrac{2s}{t}-v$

$u=\dfrac{2\times 47}{8.6}-2.3$

u = 8.63 m/s

So, the original speed of the truck is 8.63 m/s. Hence, this is the required solution.

8 0

3 years ago

Is a star's emission spectrum unique?

aliina [53]

Yessssssssssssssssssssssss

4 0

3 years ago